Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
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A finite row reduction from AA to BB is encoded by B=ErE1AB=E_r\cdots E_1A

Statement

Suppose a sequence of rr elementary row operations transforms AA into BB, and let E1,,ErE_1,\ldots,E_r be their elementary matrices in execution order. Then B=ErE1A.B=E_r\cdots E_1A. For r=0r=0 the empty product is the identity and B=AB=A.

Facts & Assumptions

Given: A finite sequence of elementary row operations taking AA to BB.

[L1]

One elementary row operation acts by left multiplication by its elementary matrix (Applying an elementary row operation is left multiplication by its elementary matrix).

[L2]

Compatible matrix multiplication is associative and has identity matrices (Matrix multiplication is associative, unital, distributive, and compatible with scalar multiplication).

[L3]

The induction principle proves a property from its zero case and successor step (The principle of mathematical induction).

Proof

technique · induction
1.1

After no operations the intermediate matrix is A=InAA=I_nA, the empty-product formula. If after kk operations it is EkE1AE_k\cdots E_1A, then [L1] says the next operation gives Ek+1(EkE1A)E_{k+1}(E_k\cdots E_1A).

L1L3baseih
2.1

Associativity rewrites the successor expression as Ek+1EkE1AE_{k+1}E_k\cdots E_1A; induction therefore gives the formula after all rr operations, including r=0r=0.

step 1.1L2discharge-induction

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 24 results over 11 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources