Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
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  • AI-adapted — a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Every invertible finite square real matrix is a finite product of elementary matrices

Statement

Every invertible matrix AMn(R)A\in M_n(\mathbb R) is a finite product of elementary matrices. The identity matrix is represented by the empty product.

Facts & Assumptions

Given: An invertible real matrix AMn(R)A\in M_n(\mathbb R).

[L2]

A row reduction is left multiplication by a product of its elementary matrices (A finite row reduction from AA to BB is encoded by B=ErE1AB=E_r\cdots E_1A).

[L4]

The real numbers form a field (The reals form a field).

Proof

technique · constructive
1.1

By [L1] row reduction takes AA to InI_n; by [L2] there are elementary real matrices with ErE1A=InE_r\cdots E_1A=I_n.

L1L2L4construct
2.1

Multiply by the explicit inverses in reverse order to obtain A=E11Er1A=E_1^{-1}\cdots E_r^{-1}, and each factor is elementary by [L3].

step 1.1L3algebra
3.1

If A=InA=I_n, take r=0r=0 and the empty product. No determinant is used.

step 2.1discharge-construct

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 56 results over 10 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources