Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-09-01
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A submersion is transverse to every embedded submanifold

Statement

If F:MN is a submersion, then FZ for every embedded submanifold ZN.

Facts & Assumptions

Given: A submersion F:MN and an embedded submanifold ZN.

[F1]

A submersion has surjective differential at every point (Immersions, submersions, and constant-rank maps).

[F2]

Transversality to Z means dFp(TpM)+TF(p)Z=TF(p)N at each point of F1(Z) (A smooth map transverse to an embedded submanifold).

Proof

technique · direct
1.1

Let pF1(Z). By [F1], dFp(TpM)=TF(p)N.

F1given
2.1

Therefore dFp(TpM)+TF(p)Z=TF(p)N, so [F2] gives FZ at p.

F2step 1.1
3.1

Since p was arbitrary, F is transverse to every embedded submanifold.

step 2.1

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources