Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Sphere self-maps of degree ±1 are exactly the homotopy equivalences

Statement

Assume ACω (The Axiom of Countable Choice (ACω)). For m≥1, a continuous self-map f:Sm→Sm is a homotopy equivalence if and only if ∣deg⁡(f)∣=1.

Facts & Assumptions

[L1]

The ambient reflection has determinant −1 and sends the outward normal x at x∈Sm to the outward normal R(x). Consequently it reverses the tangent orientation defined by placing that normal first; it is a smooth involution, hence an orientation-reversing diffeomorphism. The general diffeomorphism-degree theorem gives degree −1. (Induced boundary orientation, Degree of an orientation-preserving or reversing diffeomorphism).

Given: ACω, an integer m≥1 and a continuous self-map f:Sm→Sm (Euclidean spheres and closed balls as subspaces of Rn, Homotopy equivalences, homotopy inverses and spaces of the same homotopy type).

[F1]

Sphere self-maps are homotopic exactly when their degrees agree, and every integer occurs as a degree (Sphere self-maps are homotopic exactly when their degrees agree).

[F2]

Degree is multiplicative under composition of proper smooth maps between oriented closed manifolds and the identity has degree 1; for continuous sphere self-maps, homotopic maps have equal degree and deg⁡(g∘h)=deg⁡(g)deg⁡(h) (Degree is multiplicative under composition, Degree is homotopy invariant and multiplicative under composition, Degree of a proper smooth map by compact-support cohomology).

[F3]

The coordinate reflection R:Sm→Sm is an orientation-reversing diffeomorphism and has degree −1, and any orientation-reversing diffeomorphism between connected oriented boundaryless manifolds has degree −1 (the local calculation, Degree of an orientation-preserving or reversing diffeomorphism).

[F4]

A map homotopic to a homotopy equivalence is a homotopy equivalence, and the identity is a homotopy equivalence (A continuous map homotopic to a homotopy equivalence is itself a homotopy equivalence, Homotopy equivalences, homotopy inverses and spaces of the same homotopy type).

Proof

technique · direct
1.1F2F4given

(Necessity.) Suppose f is a homotopy equivalence with homotopy inverse g. Then g∘f≃id⁡Sm, so by [F2] applied to the continuous maps, deg⁡(g)deg⁡(f)=deg⁡(id⁡)=1 in Z; hence deg⁡(f) is a unit of Z, that is deg⁡(f)=±1.

1.2F1F4

(Degree 1.) If deg⁡(f)=1=deg⁡(id⁡), then [F1] gives f≃id⁡Sm, and since the identity is a homotopy equivalence, [F4] makes f a homotopy equivalence.

1.3L1F1F3F4

(Degree −1.) If deg⁡(f)=−1, then deg⁡(f)=deg⁡(R) for the coordinate reflection R of [F3], whose orientation reversal and degree are computed in [L1], so [F1] gives f≃R; the reflection is a diffeomorphism and hence a homotopy equivalence, so [F4] makes f a homotopy equivalence.

2.1F1F4step 1.1step 1.2step 1.3∎

Steps 1.1, 1.2 and 1.3 prove both implications, so a continuous self-map of Sm is a homotopy equivalence exactly when its degree is ±1.

Depends on

Used by

Dependency tree · two levels

38 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources