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For a C1 path the arc-length accumulation function has derivative equal to speed
Statement
Let , let be , and let
Then is differentiable on in the relative sense and
At and these are the relative one-sided derivatives.
Facts & Assumptions
Given: The path in the Statement.
The arc-length function is , with (The arc-length function of a rectifiable path).
A path has length equal to the integral of its continuous speed, including on a singleton interval where both values are zero (If is continuous, differentiable on , and extends continuously to , then ).
The integral function of an integrable function is differentiable at every point where the integrand is continuous, with derivative equal to the integrand; at endpoints this means the relative one-sided derivative (The first fundamental theorem: if is integrable on and continuous at , then ; in particular a continuous has as a primitive).
Proof
The speed is continuous because and the Euclidean norm are continuous.
By [L1] and [L2], for every , including .
Apply [L3] to step 2.1. It gives throughout , with the asserted endpoint interpretation.
Depends on
- The arc-length function $s_\gamma(t)=L(\gamma|_{[a,t]})$ of a rectifiable path
- If $\gamma:[a,b]\to\mathbb{R}^n$ is continuous, differentiable on $(a,b)$, and $\gamma'$ extends continuously to $[a,b]$, then $L(\gamma)=\int_a^b\lVert\gamma'(t)\rVert_2\,dt$
- The first fundamental theorem: if $f$ is integrable on $[a,b]$ and continuous at $c$, then $F'(c) = f(c)$; in particular a continuous $f$ has $F$ as a primitive
Used by
Nothing in the library uses this result yet.
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Sources
- J. Lebl, Basic Analysis II, section 9.2 (standard reference, not scraped)