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CorollaryStatement: AI-generatedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
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Substituting a complete or an edgeless graph for a vertex preserves the Erdős–Hajnal property

Statement

Let H be a graph with the Erdős–Hajnal property and let vV(H). If t1, then the graph obtained by substituting Kt or Kt for v also has the Erdős–Hajnal property.

Facts & Assumptions

Given: A graph H with the Erdős–Hajnal property, a vertex vV(H), and an integer t1.

[L1]

For every t1, the class of Kt-free graphs has the Erdős–Hajnal property (For every t1, the class of Kt-free graphs has the Erdős–Hajnal property).

[L2]

A graph is Kt-free exactly when its complement is Kt-free, and the Erdős–Hajnal property is preserved by taking complements of graph classes (G is H-free if and only if G is H-free, The complement of a graph class, A hereditary class has the Erdős–Hajnal property exactly when its complementary class does, with the same constants).

Proof

technique · direct
1.1

The complete graph Kt has the Erdős–Hajnal property, since every Kt-free class does by [L1].

L1
2.1

The edgeless graph Kt has the Erdős–Hajnal property: by [L2] the class of Kt-free graphs is the complementary class of the Kt-free graphs, so it has the same property.

step 1.1L2
3.1

Applying [L3] to H and Kt shows that substituting Kt for v preserves the Erdős–Hajnal property, and applying [L3] to H and Kt shows the same for the edgeless graph.

step 1.1step 2.1L3

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