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Complete splitting criterion for a cyclotomic field
Statement
Let be the conductor of the cyclotomic field , and let be a rational prime with . Then splits completely in if and only if
Facts & Assumptions
Given: The cyclotomic field presented by its conductor (Cyclotomic conductor of a full cyclotomic field), and a rational prime , so and the class of lies in .
Unramified decomposition: for the conductor and , every prime of above has residue degree and there are exactly of them; in particular is unramified (Decomposition of an unramified prime in a cyclotomic field).
Splitting terminology: a rational prime splits completely in if it is unramified in and every prime of above it has residue degree (Splitting and ramification terminology).
For a positive integer and an integer with , the order of the class equals if and only if (The order of a finite group and the order of an element, with when no positive power of is the identity, The unit group and Euler's totient for ).
( and ).
Proof
By [F1] the prime is unramified in and every prime above it has residue degree , so the primes above number .
By [F3], holds if and only if .
By [F2] and step 1.1, splits completely in if and only if every prime above has residue degree , i.e., if and only if ; equivalently (step 1.1) the number of primes above is then by [F4].
Combining steps 1.2 and 2.1: splits completely in if and only if , if and only if .
Remarks
- Consistency of counts. Complete splitting gives primes of residue degree , matching the decomposition count and the degree .
- Unramified hypothesis. The equivalence is stated for ; for the prime is ramified and the Frobenius element is not defined, by Ramification primes of a reduced cyclotomic conductor.
Depends on
- Decomposition of an unramified prime in a cyclotomic field
- Arithmetic Frobenius is the power map in an unramified cyclotomic field
- Splitting and ramification terminology
- The order $|G|$ of a finite group and the order $\operatorname{ord}(g)$ of an element, with $\operatorname{ord}(g) = \infty$ when no positive power of $g$ is the identity
- The unit group $(\mathbb{Z}/n)^\times$ and Euler's totient $\varphi(n)=\lvert(\mathbb{Z}/n)^\times\rvert$ for $n\ge1$
- $[\mathbb Q(\zeta_n):\mathbb Q]=\varphi(n)$ and $\operatorname{Gal}(\mathbb Q(\mu_n)/\mathbb Q)\cong(\mathbb Z/n)^\times$
- Cyclotomic conductor of a full cyclotomic field
Used by
- Arithmetic of Q(zeta₅) Example
- Prime decomposition in Q(zeta₁2) Example
- Prime decomposition in Q(zeta₈) Example
Dependency tree · two levels
44 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- J. S. Milne, Algebraic Number Theory, Ch. 8, Example 8.18 (standard reference, not scraped)
- Conrad-Landesman, Math 154 Algebraic Number Theory, Ch. 11, Theorem 11.6 (standard reference, not scraped)