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Arithmetic Frobenius is the power map in an unramified cyclotomic field
Statement
Let be a reduced index, that is is odd or , let be a rational prime with , let be a primitive -th root of unity and . Let be the automorphism of with . Then for every prime of above , the element is the arithmetic Frobenius : it is the unique with and for all . In particular it does not depend on the chosen prime above , the Galois group being abelian.
Facts & Assumptions
Given: A reduced index , a rational prime with , a primitive -th root of unity , the field , and the automorphism with .
, and is an integral basis (Ring of integers of every cyclotomic field).
is the monic minimal polynomial of over and has degree ( is irreducible in for every , The recursion defines a unique monic , of degree ).
is Galois with via ; this group is abelian and every automorphism has this form ( and ).
For , the reduction of in is a product of pairwise distinct monic irreducibles, each of degree (For the reduction of in is a product of distinct monic irreducibles, each of degree the order of modulo ).
Since , applying the monogenic factorisation lemma to gives where are distinct primes above , each of residue degree , where is the coefficientwise lift of with coefficients in (Choice-free prime factorisation for a monogenic number ring, Primes above and residue degree).
Over a field whose characteristic does not divide , the roots of in a splitting field of are exactly the primitive -th roots of unity. For the residue field , take a splitting field of over it; its natural field embedding is injective and preserves the multiplicative order of each element. Since has characteristic and , the theorem applies to the image of there (Over a field whose characteristic does not divide , the roots of are exactly the primitive roots of unity, The cyclotomic extension as a splitting field of ).
For a prime above an unramified rational prime in a finite Galois extension, there is a unique arithmetic Frobenius in the decomposition group satisfying for all algebraic integers (Unramified frobenius element exists uniquely).
Proof
By [F1] and [F2], the ring of integers is , the minimal polynomial of is , and its degree is . By [F3], is abelian and each automorphism is for a unit class modulo , in particular exists. If , then and the unique prime over is ; the trivial automorphism is its arithmetic Frobenius.
Since , [F4] and [F5] give with distinct primes , each of residue degree . Thus is unramified and these are all the primes above it.
Fix . By [F7] the prime has an arithmetic Frobenius satisfying the -power congruence. Evaluating it at gives
The residue class is a root of the reduction of , since . Embed the residue field into a splitting field of over it. By [F6], the image of has multiplicative order exactly there; injectivity of the field embedding gives the same order for in the residue field.
Write using [F3]. Reducing the congruence in step 1.3 gives Since has order by step 1.4, ; hence . This comparison is made directly in the residue field at , so it does not require to stabilise in advance.
The argument applies to every prime above , and each gives the same automorphism . Thus this arithmetic Frobenius is independent of the prime above , as also follows from the abelian Galois group in [F3].
Remarks
- Reduced index. The hypothesis that is odd or is the standing reduced-index convention of this pair; for the present lemma the essential hypothesis is , which makes separable modulo .
- Power map, not inverse. The identification uses the arithmetic convention ; the geometric inverse would send to and agrees with the arithmetic map exactly when , since is a unit modulo .
Depends on
- Ring of integers of every cyclotomic field
- $[\mathbb Q(\zeta_n):\mathbb Q]=\varphi(n)$ and $\operatorname{Gal}(\mathbb Q(\mu_n)/\mathbb Q)\cong(\mathbb Z/n)^\times$
- For $\gcd(n,q)=1$ the reduction of $\Phi_n$ in $\mathbb F_q[t]$ is a product of distinct monic irreducibles, each of degree the order of $[q]$ modulo $n$
- Choice-free prime factorisation for a monogenic number ring
- $\Phi_n$ is irreducible in $\mathbb Q[t]$ for every $n\ge1$
- The recursion defines a unique monic $\Phi_n\in\mathbb Z[t]$, of degree $\varphi(n)$
- Over a field whose characteristic does not divide $n$, the roots of $\Phi_n$ are exactly the primitive roots of unity
- Unramified frobenius element exists uniquely
- Primes above and residue degree
- The cyclotomic extension $K(\mu_n)$ as a splitting field of $t^{n}-1$
Used by
- Complete splitting criterion for a cyclotomic field Corollary
- Decomposition of an unramified prime in a cyclotomic field Corollary
- First supplement from Frobenius on Q(i) Corollary
- Second supplement from Frobenius on Q(zeta₈) Corollary
- Second supplement in four residue classes modulo eight Example
- Quadratic reciprocity as a Frobenius restriction identity Theorem
Dependency tree · two levels
73 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- J. S. Milne, Algebraic Number Theory, Ch. 8, Example 8.18 and Ch. 6 Remark 6.6 (standard reference, not scraped)
- Conrad-Landesman, Math 154 Algebraic Number Theory, Chs. 11-12 (standard reference, not scraped)