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CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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The contour integral of a constant c is c times the endpoint displacement

Statement

For cC and a rectifiable contour γ:[a,b]C, γcdz=c(γ(b)γ(a)).

Facts & Assumptions

Given: A complex constant c and a rectifiable contour γ.

[L1]

Constant and identity functions obey the complex derivative algebra; in particular (cz)=c (Linearity, product, reciprocal, and quotient rules for complex derivatives).

[L2]

Let F be a primitive of a continuous function f on an open set containing the trace of a rectifiable contour γ:[a,b]C. If F=f is continuous, then γf(z)dz=F(γ(b))F(γ(a)) (The line integral of a continuous function admitting a primitive is that primitive's endpoint increment along every rectifiable path).

Proof

technique · direct
1.1

By [L1], F(z)=cz is a primitive of the constant function c.

L1
2.1

The constant function c is continuous on all of C, and F=c is that same constant, so the hypotheses of [L2] hold on any open set containing the trace. Apply [L2] and simplify F(γ(b))F(γ(a))=cγ(b)cγ(a). The cases c=0 and a constant path are included.

step 1.1L2algebra

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 78 results over 14 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources