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Minimisers are classical when elliptic regularity applies

Statement

Assume the Axiom of Choice and Countable Choice. Let Ω⊆Rn, n≥2, be a bounded domain, let f and g be given and let u0∈Kg be the minimiser of the Dirichlet energy of The Dirichlet principle for the Poisson equation. Then: (i) if Ω is a bounded C∞ domain, f extends to a C∞ function on a neighbourhood of Ω‾, and there is G∈C∞(U) on a neighbourhood U of Ω‾ with G∣∂Ω=g, then u0 agrees almost everywhere with a function u~∈C∞(Ω‾) satisfying −Δu~=f pointwise in Ω and u~=g on ∂Ω (Smooth weak Dirichlet solutions are classical); (ii) if 0<α<1, Ω is a bounded C2,α domain, f∈C0,α(Ω‾) and g∈C2,α(Ω‾), then u0∈C2,α(Ω‾), −Δu0=f pointwise and u0=g on ∂Ω (Global Schauder regularity for the weak Dirichlet Laplacian). Variational existence alone gives only u0∈H1(Ω); the smoothness asserted here is a consequence of elliptic regularity and fails without the corresponding hypotheses on the domain, coefficients and data.

Facts & Assumptions

Given: The Axiom of Choice and Countable Choice; a bounded domain Ω⊆Rn, n≥2; data f and g; and the minimiser u0∈Kg of the Dirichlet energy of The Dirichlet principle for the Poisson equation. In case (i), Ω is a bounded C∞ domain, f extends smoothly to a neighbourhood of Ω‾, and G∈C∞(U) on a neighbourhood U of Ω‾ satisfies G∣∂Ω=g; in case (ii) 0<α<1, Ω is a bounded C2,α domain, f∈C0,α(Ω‾) and g∈C2,α(Ω‾).

[F2]

The trace of a smooth function is its boundary restriction, the kernel of the trace on a bounded C1 domain is H01, and H01 is the closure of Cc∞ (The trace agrees with classical restriction for continuous Sobolev functions, The kernel of the trace is the closure of the test functions, Zero-boundary Sobolev space as a norm closure).

[F3]

For G∈C∞(U) and every φ∈Cc∞(Ω), classical integration by parts gives ∫ΩDG⋅Dφ‾ dx=−∫Ω(ΔG)φ‾ dx. Both functionals extend continuously to H01(Ω) because DG∈L2 and ΔG∈L2 on the bounded domain (Holder's inequality for integrals, including the endpoint cases).

[F4]

Smooth zero-boundary elliptic regularity: on a bounded C∞ domain, a zero-trace weak solution with smooth coefficients and forcing agrees almost everywhere with a C∞(Ω‾) solution, satisfies the equation pointwise, and vanishes on the boundary (Smooth weak Dirichlet solutions are classical).

[F5]

Schauder regularity: if 0<α<1, Ω is a bounded C2,α domain and the data are Holder, then the unique weak Dirichlet solution of −Δu=f lies in C2,α(Ω‾), solves the equation pointwise and attains g classically on ∂Ω (Global Schauder regularity for the weak Dirichlet Laplacian).

Proof

technique · subtract a smooth boundary lift in the smooth case, then apply zero-boundary regularity; use the Schauder supplier directly in case (ii)
1.1F1given

The variational starting point. By [F1] the minimiser u0 is the unique weak solution of −Δu=f with trace g; the variational analysis alone gives only u0∈H1(Ω), and no higher regularity is asserted by it.

1.2F1F2F3

Case (i): lift and zero trace. Let G be the smooth extension in the hypothesis and set v:=u0−G. By [F1], Tu0=g; by [F2], TG=G∣∂Ω=g, so Tv=0 and the trace-kernel theorem gives v∈H01(Ω). For every φ∈Cc∞(Ω), [F1] and [F3] give ∫ΩDv⋅Dφ‾ dx=∫Ω(f+ΔG)φ‾ dx. Both sides are continuous in the H1 norm; density of Cc∞(Ω) in H01(Ω) extends the identity to all H01 tests. Thus v is the zero-trace weak solution with smooth forcing f+ΔG.

2.1F4step 1.2

Apply smooth regularity and restore the lift. The coefficients of −Δ are smooth, and f+ΔG extends smoothly to a neighbourhood of Ω‾. Supplier [F4] applies to v, giving a smooth representative v~∈C∞(Ω‾) with −Δv~=f+ΔG and v~=0 on ∂Ω. Then u~:=v~+G represents u0, satisfies −Δu~=f pointwise and has boundary values g.

2.2F1F5step 1.1

Case (ii). Under the Holder hypotheses of case (ii), [F5] applies to the same weak solution and yields u0∈C2,α(Ω‾) with −Δu0=f pointwise and u0=g on ∂Ω.

3.1step 1.1step 2.1step 2.2∎

The warning. Both conclusions are consequences of elliptic regularity under the stated hypotheses on the domain, the coefficients and the data; without them variational existence alone gives only u0∈H1(Ω), as the companion counterexamples on weak solutions without higher regularity record.

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