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CorollaryStatement: AI-generatedProof: AI-generatedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-26
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A linearly large induced subgraph of a graph with few induced copies again has a linearly large restricted set

Statement

Fix a graph H, a real ϵ∈(0,12), and a fraction λ>0. Then there exists δ>0 such that whenever G is a nonempty graph on n vertices with ind⁡H(G)<(δn)∣V(H)∣ and W⊆V(G) satisfies ∣W∣≥λn, the induced subgraph G[W] contains an ϵ-restricted set of size at least δ∣W∣.

Facts & Assumptions

Given: A graph H, a real ϵ∈(0,12), and a real λ>0.

[L1]

If G has n vertices, h=∣V(H)∣, ind⁡H(G)<(δn)h, and ∣W∣≥λn>0, then ind⁡H(G[W])<((δ/λ)∣W∣)h (If G has fewer than (δn)h induced copies of H and ∣W∣≥λn, then G[W] has fewer than ((δ/λ)∣W∣)h).

[L2]

There is δ0>0 such that every nonempty graph J with ind⁡H(J)<(δ0∣V(J)∣)∣V(H)∣ has an ϵ-restricted set of size at least δ0∣V(J)∣ (Nikiforov: for every H and every ϵ∈(0,12) there is δ>0 such that every graph G with ind⁡H(G)<(δ∣V(G)∣)∣V(H)∣ has an ϵ-restricted vertex set of size at least δ∣V(G)∣).

Proof

technique · direct
1.1L2choosealgebra

Let δ0 be the constant of [L2] for H and ϵ, and set δ:=min⁡{δ0,λδ0}. Then δ>0, δ≤δ0, and δ/λ≤δ0.

2.1step 1.1L1algebra

If ind⁡H(G)<(δn)∣V(H)∣ and ∣W∣≥λn, then [L1] gives ind⁡H(G[W])<((δ/λ)∣W∣)∣V(H)∣≤(δ0∣W∣)∣V(H)∣.

3.1step 1.1step 2.1L2algebra∎

Applying [L2] inside G[W] yields an ϵ-restricted set of size at least δ0∣W∣. Since δ0∣W∣≥δ∣W∣ by step 1.1, this is the required set.

Depends on

Used by

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Dependency tree · two levels

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