Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-26
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

If G has fewer than (δn)h induced copies of H and Wλn, then G[W] has fewer than ((δ/λ)W)h

Statement

Let H have h vertices. If G has n vertices, indH(G)<(δn)h, and WV(G) satisfies Wλn>0, then

indH(G[W])<((δ/λ)W)h.

Facts & Assumptions

Given: A graph H with h vertices, a graph G on n vertices, reals δ>0 and λ>0, and a subset WV(G) with Wλn and indH(G)<(δn)h.

[L1]

An induced embedding of H into G[W] is, by definition, an induced embedding of H into G whose image lies in W (Induced embeddings and induced copies of a graph, Subgraphs, induced subgraphs and spanning subgraphs).

[L2]

The induced-copy number counts induced embeddings (The induced-embedding count indH(G)).

Proof

technique · direct
1.1

By [L1], every induced embedding counted by indH(G[W]) is also counted by indH(G).

L1
2.1

Therefore indH(G[W])indH(G)<(δn)h by [L2].

step 1.1L2
3.1

Since Wλn, one has nW/λ. Substituting this into step 2.1 yields indH(G[W])<((δ/λ)W)h.

step 2.1algebra

Depends on

Used by

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources