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CorollaryStatement: Literature-sourcedProof: Literature-sourcedverified 2026-09-24 (gpt-6-sol)
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A Noetherian local domain has dimension zero exactly when it is a field

Statement

Assume the Axiom of Choice (The Axiom of Choice).

Let (R,m) be a Noetherian local domain. Then dim⁡R=0 if and only if R is a field.

Facts & Assumptions

Given: The Axiom of Choice and a Noetherian local domain (R,m).

[L1]
[L3]

Krull dimension is the supremum of lengths of strict prime chains (Krull dimension of a nonzero ring).

Proof

technique · direct
1.1L1L2L3L4given

Suppose dim⁡R=0. By [L2], the chain (0)⊆m is a prime chain. If it were strict, [L3] would give dim⁡R≥1, contradiction. Hence m=(0), so every nonzero element is outside the maximal ideal and is a unit by the AC-qualified [L4]. Thus R is a field.

1.2L1L3given

Conversely, if R is a field, its unique maximal ideal is (0). Therefore the only prime ideal is (0), and [L3] gives dim⁡R=0.

2.1step 1.1step 1.2∎

So a Noetherian local domain has dimension zero exactly when it is a field.

Depends on

Used by

Dependency tree · two levels

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Sources