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Obstacle complementarity in distribution form
Statement
Assume Countable Choice and the Axiom of Choice (The Axiom of Countable Choice (), The Axiom of Choice). Let be a bounded domain (Bounded C^k domains and boundary charts), let be a uniformly elliptic divergence-form operator with real coefficients, and let be the symmetric, bounded and coercive real restriction of its associated form (Uniformly elliptic divergence-form operators and their sesquilinear forms, Bounded C^k domains and boundary charts); let and let be its canonical functional on , so in particular for test functions (The negative Sobolev space , Locally integrable functions as regular distributions), let with (The notation and the reserved zero-boundary symbol), and let be the obstacle solution of Existence and uniqueness for the obstacle problem. For real put Extend complex linearly as in The closed convex obstacle set and the obstacle variational inequality. Then:
- is a nonnegative distribution: for every nonnegative test function (Distribution, Test function space d of an open set).
- If in addition is represented by a function , that is for every test function, and if and have continuous representatives on , then a.e., a.e. on the open set , and a.e. on .
Facts & Assumptions
Given: The obstacle setting above, with the obstacle solution of Existence and uniqueness for the obstacle problem, the reaction on , and, for the second assertion, a representation with together with continuous representatives of and on .
The closed convex obstacle set and the obstacle variational inequality, Existence and uniqueness for the obstacle problem: is nonempty, and satisfies for every (Zero-boundary Sobolev space as a norm closure); the inequality and the membership are almost-everywhere statements about classes.
A function with nonnegative test pairings is nonnegative a.e.: if and for every nonnegative , then a.e. on .
The fundamental lemma of the calculus of variations: if and for every , then a.e. on ; in particular by the finite measure of the bounded domain.
Uniformly elliptic divergence-form operators and their sesquilinear forms: the real Dirichlet form is used only on ; under the stated hypotheses it is a bounded, coercive symmetric real bilinear form there, and the associated form on restricts to it. In particular, both the obstacle solution and each test function lie in the form domain.
The negative Sobolev space : in the real convention, every defines in , with and hence .
Proof
Given: The setting above, in particular the obstacle solution and the reaction .
(Nonnegativity) Let with , and put . Then because and , and a.e. on , so [F1]. By [F5], is the continuous functional used by the variational inequality; testing that inequality at gives , that is ; hence is a nonnegative distribution.
(Vanishing on the noncontact set) Assume now that for all test functions and that have continuous representatives, and put , an open subset of because the difference of the continuous representatives is continuous and positive exactly on . Let be arbitrary. If , then . Otherwise its support is a nonempty compact subset of ; as is continuous and positive there, there is with on . Choose with . Then on , while on one has a.e.; also . Hence both competitors belong to [F1]. Testing the variational inequality at them gives and , so ; that is, for every .
For the second assertion, the hypothesis of the representation gives for every nonnegative test function by step 1.1, so [F2] applied with yields a.e. on .
Step 1.2 gives for every with ; consequently [F3] yields a.e. on .
Finally a.e. on : on this follows from a.e. by step 2.2, and on the class vanishes a.e. — indeed a.e. by [F1] while on one has pointwise for the continuous representatives, so the set where is contained in the complement of and is null.
Step 1.1 proves the nonnegativity of the reaction, step 2.1 the a.e. nonnegativity of its representative, step 2.2 its vanishing on the noncontact set and step 3.1 the complementarity product; all three conclusions of the second assertion use exactly the stated -representation and continuity hypotheses, and no product of a distribution with a Sobolev class is formed.
Depends on
- The Axiom of Choice
- Bounded C^k domains and boundary charts
- The closed convex obstacle set and the obstacle variational inequality
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- Distribution
- The negative Sobolev space $H^{-1}(\Omega)$
- The notation $H^k$ and the reserved zero-boundary symbol
- Locally integrable functions as regular distributions
- Test function space d of an open set
- Uniformly elliptic divergence-form operators and their sesquilinear forms
- Zero-boundary Sobolev space as a norm closure
- The fundamental lemma of the calculus of variations
- A function with nonnegative test pairings is nonnegative a.e.
- Existence and uniqueness for the obstacle problem
Used by
- The obstacle reaction is supported on the contact set under measure regularity Corollary
- The complementarity product needs extra regularity Counterexample
- The one-dimensional obstacle reaction is supported on the contact set Example
- Pointwise and integral constraints have different regularity tests Remark
- Lewy–Stampacchia distribution bound for bounded-coefficient obstacle forms Theorem
Dependency tree · two levels
63 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- John Andersson, The Obstacle Problem, KTH lecture notes, 16 December 2015 (complete 52-page notes) (standard reference, not scraped)
- Gerald Teschl, Partial Differential Equations: From Classical to Modern (2026 author manuscript; complete 392-page archived text) (standard reference, not scraped)