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CorollaryStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
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Q_p is locally compact and totally disconnected

Statement

Assume the Axiom of Countable Choice ACω of The Axiom of Countable Choice (ACω). Then the field Qp is locally compact and totally disconnected. In particular, Zp is a compact open subring.

Facts & Assumptions

Given: The p-adic field Qp and ACω.

[L1]

Zp={x:xp1}, and p-adic balls are clopen (Z_p is the valuation ring of Q_p, P-adic balls are clopen and intersecting comparable balls are nested).

[L2]

Every element of Zp has a digit expansion (Every p-adic number has a unique digit expansion).

[L3]

Assuming ACω, a complete totally bounded metric space is compact (A complete, totally bounded metric space is compact, proved from countable choice used exactly once).

Proof

technique · direct
1.1

By [L1], Zp is the closed unit ball, and by the clopen-ball lemma it is open. To prove compactness, note first that Zp is complete as a closed subset of the complete field Qp. It is totally bounded because for each N1, every element of Zp differs by at most pN from one of the finitely many truncations a0+a1p++aN1pN1 with digits ai{0,,p1}, by [L2]. Hence [L3] makes Zp compact.

L1L2L3givenalgebra
2.1

Every point of Qp has a compact open neighborhood, namely a scalar multiple of Zp, so Qp is locally compact. If xy, choose a ball around x whose radius is smaller than xyp; by [L1] this ball is clopen and does not contain y. Therefore points are separated by clopen sets, so Qp is totally disconnected.

L1step 1.1algebra

Depends on

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