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CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck pendingjudge pass (gpt-6-luna)
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Independent RQMC replicates estimate randomization variance

Statement

Fix the observed data and an integrable RQMC target I=I(f). Suppose one full-set randomization produces an estimator I^ with E[I^]=I and finite variance τ2. For R≥2 independent full-set randomizations, write their IID estimates as I^1,…,I^R and their mean as I‾R=R−1∑r=1RI^r. Then V^R=1R(R−1)∑r=1R(I^r−I‾R)2 is unbiased for Var⁡(I‾R)=τ2/R. This variance is over computation randomization conditional on the fixed data and rule; it does not include data-sampling variation.

Facts & Assumptions

Given: The fixed target, an RQMC estimator with mean I and finite variance, and R≥2 independent full-set randomizations.

[F1]

Randomized quasi-Monte Carlo point sets and estimators: An independent full-set randomization is an independent copy of the entire point-array vector.

[F2]

Marginal uniformity makes an RQMC rule unbiased: A single marginally uniform rule has expectation I(f) for every Borel integrable f.

[F3]

Unbiased variance estimate from independent computation replicates: For IID real Z1,…,ZR with finite variance, [R(R−1)]−1∑r(Zr−Z‾R)2 is unbiased for Var⁡(Z‾R).

[F4]

Moments, variance, and covariance on a probability space: Variance is E[(Z−EZ)2] for a square-integrable real variable.

Proof

technique · direct

Given: The hypotheses in the Statement.

1.1F1F2F3F4given

By [F1], independent full-set randomizations give independent estimates with the same law. By [F2] their common mean is I, and the stated finite variance supplies the moment hypothesis of [F3].

2.1F3givenalgebra∎

Apply [F3] to Zr=I^r. It gives E[V^R]=Var⁡(I‾R). Independence and the common variance τ2 give Var⁡(I‾R)=R−2∑rVar⁡(I^r)=τ2/R. Since the data are fixed in the probability law of these replicates, this variance concerns randomization only.

Depends on

Used by

Dependency tree · two levels

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Sources