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Any two splitting fields of a polynomial are isomorphic over the base field
Statement
If and are splitting fields of the same nonzero polynomial , then there is a field isomorphism that fixes pointwise.
Facts & Assumptions
Given: Two splitting fields and of the same nonzero polynomial.
A base-field isomorphism extends to an isomorphism between splitting fields of the corresponding transported polynomials (A base-field isomorphism extends to an isomorphism between splitting fields of corresponding polynomials).
Proof
Apply [F1] to the identity isomorphism of . It transports to itself and therefore extends to an isomorphism fixing .
This includes nonzero constants, whose splitting fields have empty root sets and both equal .
Depends on
Used by
- The cyclotomic extension K(μₙ) as a splitting field of tⁿ-1 Definition
- The splitting field of x³-2 over ℚ is ℚ(³√2,ω) with ω=(-1+i√3)/2 Example
- FALSE: the isomorphism between two splitting fields that fixes the base field is unique False statement
- Finite fields of the same order are isomorphic Theorem
- The separable degree is independent of the chosen algebraic closure Theorem
Dependency tree · two levels
8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- T. Judson, Abstract Algebra: Theory and Applications, Corollary 21.14 (standard reference, not scraped)