Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-31
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The immersion and submersion loci are open

Statement

Let F:MmNn be a smooth map. The set of points where F is an immersion is open in M, and the set of points where F is a submersion is open in M.

Facts & Assumptions

Given: A smooth map F:MmNn.

[F1]

F is an immersion at p exactly when rankpF=m, and it is a submersion at p exactly when rankpF=n (Immersions, submersions, and constant-rank maps).

[L1]

For a smooth Euclidean map, the locus where the differential has rank at least a fixed integer is open (Differential rank is lower semicontinuous).

[L2]

Every manifold chart is a diffeomorphism onto an open Euclidean set (Chart maps are diffeomorphisms onto Euclidean open sets).

Proof

technique · direct
1.1

Fix an immersion point p. Choose charts around p and F(p) as in [L2], and let f be the coordinate representative of F. Then rankDf(φ(p))=m by [F1]. Since the differential of a map RmRn cannot have rank above m, [L1] gives a Euclidean neighbourhood on which the rank stays at least m, hence exactly m.

F1L1L2given
1.2

The same argument with n in place of m shows that near any submersion point the rank stays equal to n, so the submersion locus is open. Here the upper bound rankDfn is the relevant maximal-rank bound.

F1L1L2given
2.1

Translating step 1.1 back through the source chart, every point of a smaller neighbourhood of p is again an immersion point. Hence the immersion locus is open.

step 1.1L2
3.1

Steps 2.1 and 1.2 prove the two openness claims.

step 2.1step 1.2

Depends on

Used by

Dependency tree · two levels

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