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PropositionStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-09-01
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Transversality is stable on a compact source

Statement

Let M be compact, let Z⊆N be a closed embedded submanifold, and let F:M→N be smooth with F⋔Z. Then every smooth map G:M→N sufficiently close to F in the C1 topology is also transverse to Z.

Facts & Assumptions

Given: A compact manifold M, a closed embedded submanifold Z⊆N, and a smooth map F:M→N with F⋔Z.

[F1]

Transversality at a point is equivalent to surjectivity of the induced map to the normal quotient (Transversality is equivalent to surjectivity on the normal quotient).

[L1]

Embedded submanifolds admit local defining submersions, and the submersion locus is open (Embedded submanifolds admit local defining submersions, The immersion and submersion loci are open).

Proof

technique · direct
1.1givenchoose

If F(p)∉Z, closedness of Z gives a neighbourhood Vp of F(p) disjoint from Z. Shrink to a relatively compact neighbourhood Up of p with F(Up‾)⊆Vp. Every map G sufficiently C0-close to F on Up‾ still maps Up into Vp, so transversality there is vacuous.

1.2F1L1givenchoosealgebra

If F(p)∈Z, choose a neighbourhood Vp of F(p) and a defining submersion hp:Vp→Rcp for Z by [L1]. Because F⋔Z, the composite hp∘F is a submersion at p by [F1]. In source and target coordinates, some cp×cp minor of D(hp∘F) is nonzero at p. Shrink to a relatively compact Up so that F(Up‾)⊆Vp and this minor stays nonzero on Up‾, using the fixed-map openness in [L1]. If G is sufficiently C1-close to F on Up‾, then G(Up‾)⊆Vp and the corresponding minor of D(hp∘G) remains nonzero. Thus hp∘G is a submersion on Up, and G⋔Z there.

2.1step 1.1step 1.2givenchoose

The sets Up from steps 1.1 and 1.2 cover the compact manifold M, so a finite subcover suffices. Intersect the corresponding finitely many C1 neighbourhoods of F. Any G in that intersection is transverse to Z on each Up, hence on all of M.

3.1step 2.1∎

Therefore transversality is stable on a compact source in the C1 topology.

Depends on

Used by

Dependency tree · two levels

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Sources