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Uniqueness implies existence for the elliptic Dirichlet problem

Statement

Assume the Axiom of Choice and Countable Choice. In the setting of The Fredholm alternative for weak elliptic Dirichlet problems suppose both homogeneous problems are trivial: a(u,v)=0 for all v∈H01(Ω) implies u=0, and a∗(v,w)=0 for all w∈H01(Ω) implies v=0 (the two conditions are equivalent by the finite dimension and equality of dimensions in The elliptic kernel and cokernel are finite dimensional). Then for every f∈L2(Ω) there is exactly one u∈H01(Ω) with a(u,v)=(f,v)L2 for all v∈H01(Ω). Moreover the solution map f↦u is a bounded linear operator from L2(Ω) to H01(Ω): explicitly u=Kμ(I−μKμ)−1f for every admissible μ≥β, with (I−μKμ)−1 bounded on L2(Ω) (The shifted elliptic solution operator, Neumann series and small perturbations of bounded inverses).

Facts & Assumptions

Given: the Axiom of Choice and Countable Choice; a bounded open set Ω⊆Rn; the weak Dirichlet problem for form a and adjoint a∗; a fixed μ≥β; the compact operator μKμ on L2(Ω); and the assumption that both homogeneous problems are trivial.

[F1]

Fredholm alternative: exactly one of the alternatives of The Fredholm alternative for weak elliptic Dirichlet problems holds; alternative (2) holds exactly when the homogeneous problem has a nonzero solution; alternative (1) gives existence and uniqueness for every f∈L2(Ω).

[F2]

The homogeneous space N of [F1] equals ker⁡(I−μKμ), and u is a weak solution with datum f exactly when (I−μKμ)u=Kμf (On bounded domains, the unshifted equation is an identity-minus-compact equation, The elliptic kernel and cokernel are finite dimensional, The shifted elliptic solution operator).

[F3]

Abstract Fredholm alternative: for a compact K on a Banach space, I−K is injective if and only if it is surjective, and then it is boundedly invertible (Fredholm alternative for identity minus compact, Bounded inverse theorem, Neumann series and small perturbations of bounded inverses).

[F4]

Bounded linear operators compose to bounded linear operators, and Kμ:L2(Ω)→H01(Ω) is bounded linear (A bounded linear operator between normed spaces, The shifted elliptic solution operator).

Proof

technique · direct
1.1F1F2given

Existence and uniqueness. If the homogeneous problem is trivial then N={0}=ker⁡(I−μKμ) by [F2], so alternative (2) of [F1] is excluded; by the dichotomy of [F1] alternative (1) holds. Hence for every f∈L2(Ω) the weak problem has exactly one solution u∈H01(Ω). The triviality of the adjoint homogeneous problem is not needed for this conclusion, and the two triviality hypotheses are equivalent by The elliptic kernel and cokernel are finite dimensional.

2.1F2F3F4step 1.1givenalgebra

Bounded solution map. Under the hypothesis N={0} the operator A:=I−μKμ is injective on L2(Ω), so [F3] makes it boundedly invertible there; since u is a weak solution with datum f exactly when Au=Kμf by [F2], the unique solution is u=A−1Kμf. The operator Kμ commutes with A=I−μKμ, hence also with A−1, so u=KμA−1f. Both factors in this expression are bounded linear operators, with Kμ mapping into H01(Ω) by [F4], so f↦u is a bounded linear operator from L2(Ω) to H01(Ω); the expression is independent of the admissible shift because u is.

3.1F1F3step 1.1step 2.1given∎

Conclusion. Steps 1.1 and 2.1 give existence, uniqueness and the bounded solution map for every f∈L2(Ω), with the explicit representation u=Kμ(I−μKμ)−1f; no compactness is used beyond the Fredholm alternative inherited from μKμ, and the Axiom of Choice supplies the hypotheses of the Rellich compactness and abstract Fredholm suppliers.

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