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Compactly supported de Rham cohomology
Definition
Let be a finite-dimensional Hausdorff second-countable smooth manifold, possibly with boundary. Let be the smooth -forms with compact support in , and put it equal to zero for or . With the locally extendible boundary convention, exterior differentiation restricts to these spaces and gives the compactly supported de Rham complex . Its cohomology is Thus equality of two closed compactly supported representatives requires a compactly supported primitive for their difference. If is compact this is the ordinary de Rham complex and cohomology. No orientation or choice axiom is required.
Facts & Assumptions
Compact support of a differential form defines support as the closure in of the nonzero locus and includes genuine boundary points; zero has empty support.
De rham cochain complex gives the ordinary boundaryless complex and degree convention.
The de Rham complex and pullback extend to manifolds with boundary supplies the linear local derivative and , also at a boundary.
Interior, closure, boundary, exterior, derived set and isolated point in a topological space gives the smallest-closed-superset property and the open complement of a closure.
A subspace is compact exactly when every family of open subsets of the ambient space covering it, indexed or not, has finitely many members covering it permits testing compact subsets using covers by opens of the ambient space.
Verification
Given: as stated and compactly supported forms of the same degree.
For scalars , the nonzero locus of is contained in , a closed set by [F4]. Its closure is therefore contained there too. The union is compact: restrict any ambient open cover to its two compact subsets, take a finite subcover for each by [F5], and unite those two finite families. A closed subset of this compact union is compact as well: adjoin the open set to an ambient cover of , take a finite subcover of the union and discard that added member. By [F5] this is the intrinsic compactness of . Applying this to the closed support of proves that is a vector subspace. The empty support includes zero.
Outside the form is identically zero on the open complement supplied by [F4]. The local coefficient formula in [F3] makes zero on that same open set, including any boundary-chart points. Thus its nonzero locus lies in the closed set , and so does its closure: The support on the left is a closed subset of the compact support on the right, hence compact by the cover argument in step 1.1. Therefore restricts to the stated subspaces.
The restricted differential is linear and squares to zero by [F3]. Its image in degree is consequently a vector subspace of its kernel, so the displayed quotient is defined. Two closed representatives differ by zero in this quotient exactly when their difference equals for some ; a primitive without compact support does not satisfy this definition. When is compact, every support is closed in , so step 1.1 makes it compact and in every degree. By [F2] and [F3] the complexes and their quotients then agree.
On the empty manifold all spaces are zero. In degree zero the denominator is zero because ; in degree one it consists exactly of differentials of compactly supported functions. In dimension zero there are no positive-degree forms. In top degree the outgoing derivative is zero, while the incoming compact-support requirement remains in force. All support statements are intrinsic and independent of coordinates; no orientation, countable family of primitives or partition of unity was used.
Depends on
- Compact support of a differential form
- De rham cochain complex
- The de Rham complex and pullback extend to manifolds with boundary
- Interior, closure, boundary, exterior, derived set and isolated point in a topological space
- A subspace is compact exactly when every family of open subsets of the ambient space covering it, indexed or not, has finitely many members covering it
Used by
- Top de Rham cohomology of a closed connected oriented manifold is real Corollary
- Compactly supported de Rham cohomology is contravariant for proper smooth maps Proposition
- Proper smooth maps pull back compactly supported forms Proposition
- Integration descends to compactly supported top de Rham cohomology Theorem
- Integration is an isomorphism on top compactly supported de Rham cohomology Theorem
Dependency tree · two levels
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Sources
- Robbin–Salamon, Introduction to Differential Topology (standard reference, not scraped)