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(1+x2)1dx\int_{-\infty}^{\infty}(1+x^2)^{-1}\,dx converges absolutely

Example

The whole-line integral dx1+x2\int_{-\infty}^{\infty}\frac{dx}{1+x^2} converges absolutely. No evaluation of its value is needed.

Facts & Assumptions

Given: f(x)=(1+x2)1f(x)=(1+x^2)^{-1} on R\mathbb R.

[L2]

For x1|x|\ge1, 0<f(x)x20<f(x)\le x^{-2}.

[L3]

The p=2p=2 tail integral converges, and comparison transfers convergence (The improper pp-test for rational exponents, Comparison tests for improper integrals).

Verification

technique · direct
1.1

By [L1], the integral over [1,1][-1,1] is proper. On [1,)[1,\infty), [L2] and [L3] prove convergence. Substitution t=xt=-x gives the identical conclusion on (,1](-\infty,-1].

L1L2L3
2.1

Since f0f\ge0, f=f|f|=f. Both tails converge separately and the middle piece is proper, so the mixed integral is absolutely convergent by definition.

given

Depends on

Used by

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Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 123 results over 25 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources