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The Bernoulli sample mean

Example

Let X={0,1} with its power-set sigma-algebra. For p∈[0,1], define the Bernoulli law Pp({1})=p and Pp({0})=1−p, and use the estimand ψ(p)=p. Suppose a common probability space carries an IID sequence with one-observation law Pp. Under its IID sample-size experiments, the estimator Tn(x1,…,xn)=n−1∑i=1nxi is the sample proportion. It satisfies the finite-sample bound Pp⊗n(∣Tn−p∣≥ε)≤p(1−p)nε2≤14nε2,ε>0, so it is consistent, including at p=0 and p=1.

Facts & Assumptions

Given: p∈[0,1], the two-point observation space, the displayed Bernoulli masses, and a common probability space carrying an IID sequence with law Pp.

[F1]

Sigma-algebras: The power set of a set is a sigma-algebra.

[F2]

Measurable spaces and measurable sets: A measurable space is a set together with a sigma-algebra.

[F3]

Measures on sigma-algebras: A measure assigns zero to the empty set and is countably additive on pairwise disjoint measurable sets.

[F4]

Probability measures and probability spaces: A probability measure is a measure of total mass one.

[F5]

Statistical experiments: An experiment is a measurable observation space and a parameter-indexed family of probability measures on it.

[F6]

Parametric statistical models: The model is the parameter map p↦Pp.

[F7]

Estimands on a statistical model: An estimand is a specified function from the parameter set to a target set.

[F8]

Estimator sequences in IID experiments: Under IID sampling, the size-n law is Pp⊗n and an estimator is a measurable map on Xn.

[F9]

Partial sums, row sums and sample means: For real random variables, X‾n=n−1∑i=1nXi is the sample mean.

[F10]

Identical distribution and IID families: IID means identical laws and mutual independence.

[F11]

Independent random elements have product joint law: A finite independent family has joint law equal to the product of its marginal laws.

[F12]

The integral of a nonnegative simple function: The integral of a nonnegative simple function is the sum of its values times the measures of the corresponding disjoint level sets.

[F13]

Moments, variance, and covariance on a probability space: For square-integrable X, Var⁡(X)=E[(X−EX)2].

[F14]

IID finite-variance weak law: For IID square-integrable real variables with variance σ2, P(∣X‾n−EX1∣≥ε)≤σ2/(nε2).

[F15]

Consistency of the IID sample mean under a finite first moment: An IID real sample with finite first absolute moment has a sample mean consistent in probability for its mean.

[F16]

Pointwise consistency in probability: Consistency at p means the probability of an estimation error greater than each fixed ε>0 tends to zero under Pp⊗n.

[F17]

The product sigma-algebra and its finite iterates: The finite product sigma-algebra is generated by measurable rectangles, so its coordinate projections are measurable.

[F18]

Arithmetic and lattice operations preserve measurability whenever they are defined: Pointwise sums and real scalar multiples of measurable real-valued functions are measurable whenever defined.

Verification

1.1F1F2F3F4F5F6F7given

The power set of {0,1} is a sigma-algebra by [F1], so it defines a measurable space by [F2]. Because 0≤p≤1, the two singleton masses are nonnegative and sum to one. For any pairwise disjoint sequence of subsets, each of 0 and 1 occurs in at most one set, so the mass formula is countably additive and gives zero to the empty set by [F3]. Thus Pp is a probability measure by [F4], and the family is a statistical experiment with model map p↦Pp and target ψ(p)=p by [F5, F6, F7].

1.2F12F13givenalgebra

For X∼Pp, X=1{1} and X2=X, so [F12] gives EpX=p and EpX2=p. By [F13], Var⁡p(X)=p−p2=p(1−p), which is finite for all p∈[0,1].

2.1F8F9F10F11F14F17F18step 1.2givenalgebra

By [F17], each coordinate projection on Xn is measurable; [F18] makes their finite sum and scalar multiple Tn measurable, as required by [F8]. The displayed map is the sample mean of [F9]. The given common sequence satisfies the IID hypothesis of [F14] by [F10], and [F11] identifies the law of its first n observations with Pp⊗n. Applying [F14] with σ2=p(1−p) from step 1.2 and transferring through this joint-law identity gives Pp⊗n(∣Tn−p∣≥ε)≤p(1−p)/(nε2). Since p(1−p)=1/4−(p−1/2)2≤1/4, this is at most 1/(4nε2).

3.1F8F11F15F16step 1.2step 2.1givenalgebra∎

For fixed ε>0, the bound in step 2.1 tends to zero, so [F16] gives consistency; this is also the special case of [F15]. By [F8] and [F11], at p=0 and p=1 the product law assigns probability one to the all-zero and all-one samples respectively, so Tn=p almost surely at each endpoint. For the finite check n=2,p=1/2, the same rectangle formula gives mass 1/4 to each ordered pair, hence T2 has masses 1/4,1/2,1/4 at 0,1/2,1; the probability of error at least 1/2 is 1/2, matching the bound in step 2.1.

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