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Cost-constrained capacity of a binary identity channel with feedback

Example

Let X=Y={0,1}, let W(y∣x)=1{y=x}, and let c(0)=0,c(1)=1. For every budget Γ≥0, both ordinary and feedback capacities are C(Γ)=Cfb(Γ)=h2(min⁡{Γ,1/2}), where h2(p)=−pln⁡p−(1−p)ln⁡(1−p) and 0ln⁡0=0. In particular the values at Γ=0,1/2,1 are 0,ln⁡2,ln⁡2.

Facts & Assumptions

Given: The binary identity transition law, letter costs 0,1, and a nonnegative budget Γ.

[F1]

Finite DMC with a nonnegative input cost and feasible budget: an input law with p=PX(1) has expected cost p.

[F2]

Finite entropy and mutual-information chain rules: for the identity channel, I(X;Y)=H(X)−H(X∣Y)=H(X).

[F3]

Finite-simplex entropy is continuous and concave: binary entropy is continuous, concave, and symmetric under p↦1−p by its formula.

[F4]

Average-cost fixed-length codes and operational DMC capacity, Average-cost capacity formula for a finite DMC, and Causal feedback does not increase finite DMC capacity under average cost: ordinary and feedback capacities use the stated average-cost conventions and equal the maximum feasible mutual information: ordinary and feedback capacities equal the maximum feasible mutual information.

Verification

1.1F1F2F3F5givenalgebra

An input law is feasible exactly when 0≤p≤min⁡{Γ,1}, and [F2] makes its mutual information h2(p). If 0≤p≤q≤1/2 and p<1/2, put θ=(1−p−q)/(1−2p)∈[1/2,1]. Then q=θp+(1−θ)(1−p); concavity and symmetry in [F3] imply h2(q)≥θh2(p)+(1−θ)h2(1−p)=h2(p). Thus h2 is nondecreasing on [0,1/2].

2.1F1F3F5step 1.1givenalgebra

For any p∈[0,1], concavity and symmetry give h2(1/2)≥12h2(p)+12h2(1−p)=h2(p). Therefore the maximum over the feasible interval occurs at p=min⁡{Γ,1/2} and equals the displayed formula. Substitution yields C(0)=0, C(1/2)=ln⁡2, and C(1)=ln⁡2.

3.1F4step 2.1given∎

The feedback theorem in [F4] makes the feedback capacity equal to the same ordinary constrained capacity. This identifies the values for all three requested budgets.

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