Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-adaptedPipeline-generatedverified 2026-09-24 (gpt-6-sol)
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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completion regularity invariance

Example

Assume the Axiom of Choice (The Axiom of Choice). The ring R=k[x,y](x,y) and its completion k[ ⁣[x,y] ⁣] both have dimension and embedding dimension two. For every q≥1, their quotients by the qth powers of the maximal ideals agree and have basis the monomials of total degree less than q.

Facts & Assumptions

Given: The objects and hypotheses in the example. We work with the Axiom of Choice; cited dependent-choice and resolution-existence hypotheses are retained.

[F1]

completion preserves embedding dimension: For a nonzero Noetherian local ring (R,m,k), its maximal-adic completion R^ has maximal ideal m^=mR^, residue field k, and a canonical isomorphism m/m2≅m^/m^2. In particular their embedding dimensions agree.

[F2]

completion preserves regular local rings: A nonzero Noetherian local ring R is regular if and only if its maximal-adic completion R^ is regular.

[F3]

Completion of a Noetherian local ring is local with the same residue field: Assume the Axiom of Choice. Let (R,m) be a Noetherian local ring, and let R^ be its m-adic completion. 1. R^ is a Noetherian local ring with maximal ideal mR^. 2. The residue field is unchanged: R^/mR^≅R/m. 3. The completion map R→R^ is faithfully flat.

[F4]

Completion preserves dimension and Hilbert-Samuel data: Assume the Axiom of Choice. Let (R,m) be a Noetherian local ring, let M≠0 be a finitely generated R-module, and let R^, M^ denote the m-adic completions. 1. For every n≥0, M^/mn+1M^≅M/mn+1M. In particular the Hilbert-Samuel functions of M and M^ agree. 2. The Hilbert-Samuel multiplicity of M equals that of M^. 3. The support dimensions of M and M^ are equal.

[F5]

dimension at most embedding dimension: Every nonzero commutative Noetherian local ring R satisfies dim⁡R≤edim⁡R<∞.

Verification

1.1givenalgebra

Degree truncation identifies series modulo (x,y)q with polynomials modulo that ideal. In the truncated polynomial ring, every denominator allowed in R is a unit, by a finite geometric-series expansion of its nonconstant part. Thus both quotients have the stated monomial basis, and their inverse limit is k[ ⁣[x,y] ⁣], identifying it as the maximal-adic completion.

2.1F1F4F3F2F5step 1.1∎

The coordinate chain and two maximal-ideal generators give dim⁡R=edim⁡R=2. The cotangent-completion theorem preserves embedding dimension and the completion dimension theorem preserves dimension independently. The completion is Noetherian local and regular. At q=1 the quotient is k; at q=2 the basis 1,x,y exhibits the two cotangent classes.

Depends on

Used by

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Sources