Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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completion preserves regular local rings

Statement

A nonzero Noetherian local ring R is regular if and only if its maximal-adic completion R^ is regular.

Facts & Assumptions

Given: The objects and hypotheses in the statement. We work with the Axiom of Choice; cited dependent-choice and resolution-existence hypotheses are retained.

[F1]

completion preserves embedding dimension: For a nonzero Noetherian local ring (R,m,k), its maximal-adic completion R^ has maximal ideal m^=mR^, residue field k, and a canonical isomorphism m/m2m^/m^2. In particular their embedding dimensions agree.

[F2]

Completion preserves dimension and Hilbert-Samuel data: Assume the Axiom of Choice. Let (R,m) be a Noetherian local ring, let M0 be a finitely generated R-module, and let R^, M^ denote the m-adic completions. 1. For every n0, M^/mn+1M^M/mn+1M. In particular the Hilbert-Samuel functions of M and M^ agree. 2. The Hilbert-Samuel multiplicity of M equals that of M^. 3. The support dimensions of M and M^ are equal.

Proof

1.1

Completion preserves the embedding dimension. Applied to the nonzero finite module R, the completion dimension theorem also gives dimR^=dimR, because the support of a ring over itself is its entire spectrum.

F1F2
2.1

Thus edimR=dimR holds exactly when edimR^=dimR^. These are the two regularity conditions. The argument also applies when the common dimension or embedding dimension is zero.

step 1.1algebra

Depends on

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Dependency tree · two levels

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Sources