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Dyadic conditional expectation martingale
Example
Assume AC. On with Lebesgue probability, let for and let be their finite-partition sigma-algebra. For real , is a version of , and is a martingale.
Facts & Assumptions
Given: The hypotheses and conventions in the example.
Under countable choice Lebesgue measure exists and agrees with half-open interval length. Assuming countable choice, is a sigma-algebra containing every elementary set and is a complete measure extending elementary volume.
Restriction of a measure to a measurable set is a measure. The restriction of a measure to a measurable set is a measure.
Under AC every integrable input has a measurable integrable conditional version. Conditional expectation as an ae class.
Finite linear combinations remain integrable and their integrals are linear. The Lebesgue integral is linear on .
The absolute integral is bounded by the integral of the absolute value. The modulus of an integral is bounded by the integral of the modulus.
Conditional expectations of a fixed L1 variable along a filtration form a martingale. Conditional expectation process is a martingale.
AC supplies the inherited conditional-expectation existence and any stated choice of versions. The Axiom of Choice.
Verification
First justify the finite integral operations locally. Augment every finite disjoint simple display by the complement with coefficient . Intersections of two augmented displays partition the whole space and have equal coefficients on every nonempty cell, so finite additivity and prove representation independence. Common refinements give simple addition and monotonicity; scalar zero is direct and positive scalars are termwise. Supremum over simple minorants, increasing simple approximation and the sets , , give monotone convergence and nonnegative additivity. Positive/negative and real/imaginary decompositions give the finite linearity and triangle estimate used below. The trace restriction of Lebesgue measure to has total mass one. The displayed half-open cells Half-open boxes in and their volume are disjoint, exhaust the space and have probability . Their unions form a sigma-algebra because unions and complements select cells from a finite partition. Each cell at n is exactly the union of its children at n+1, so the sigma-algebras increase. Every cell integral of is finite. The displayed finite-valued is -measurable, and .
For , finite addition and the cell mass give . Thus meets every defining conditional-expectation requirement. Apply [F6] to obtain the martingale. For , the first average is and every finer cell lies entirely in or its complement, so for . In particular . AC supplies the Lebesgue construction and CE existence; the explicit finite averages require no version selection.
Depends on
- Conditional expectation process is a martingale
- Assuming countable choice, $\mathcal{L}(\mathbb{R}^n)$ is a sigma-algebra containing every elementary set and $\lambda_n$ is a complete measure extending elementary volume
- Half-open boxes in $\mathbb{R}^n$ and their volume
- The restriction of a measure to a measurable set is a measure
- Conditional expectation as an ae class
- Conditional expectation is unique almost surely
- The Lebesgue integral is linear on $L^1(\mu)$
- The modulus of an integral is bounded by the integral of the modulus
- The Axiom of Choice
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
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Sources
- van der Vaart, Martingales, Diffusions and Financial Mathematics (standard reference, not scraped)