Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-12
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Conditional expectation process is a martingale

Statement

Assume AC. For X∈L1(P) on a discrete filtered probability space, choose at each n≥0 a real Fn-measurable version Mn of E[X∣Fn]. Then M is a martingale.

Facts & Assumptions

Given: The hypotheses and conventions in the statement.

[F1]

Under AC every integrable input has a measurable integrable conditional version. Conditional expectation as an ae class.

[F2]

Conditional expectations on nested sigma-algebras satisfy the tower identity. Tower property of conditional expectation.

[F3]

AC supplies the inherited conditional-expectation existence and any stated choice of versions. The Axiom of Choice.

[F4]

A countable union of measurable null sets is null. Finite and countable subadditivity of measures.

Proof

technique · direct
1.1givenF1F3

By conditional existence the set of real measurable integrable versions at every time is nonempty. AC selects one member for each n∈N0. Thus each Mn is Fn-measurable and integrable, so M is an integrable adapted process. AC also covers the RN existence assumption.

2.1F1F2F4step 1.1∎

Since Fn⊆Fn+1, the tower identity gives E[Mn+1∣Fn]=E[E[X∣Fn+1]∣Fn]=E[X∣Fn]=Mn a.s. for each n≥0. This is the martingale condition Martingale submartingale and supermartingale. If representatives of these identities are specified, their measurable failure sets have probability zero; their countable union is measurable and null. This does not complete any Fn or alter its representatives.

Depends on

Used by

Dependency tree · two levels

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Sources