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The unit-circle integral of exp(z)/z is 2 pi i by uniform termwise integration
Example
On the positively oriented unit circle ,
Facts & Assumptions
Given: The positively oriented unit circle.
The complex exponential is the series (The complex exponential by its power series), and this series converges absolutely for every complex (The complex exponential series converges absolutely for every complex argument).
Complex line integrals are linear in the integrand (Complex line integrals are linear in the integrand).
Uniform convergence on a fixed contour permits passage of the limit through the line integral (A uniformly convergent sequence of continuous integrands on a fixed contour permits passage of the limit through the complex line integral).
On a positive circle, the integral of is for integer and for (On a positively oriented circle about a, the integral of (z-a)^m is zero for every integer m except -1, and is 2 pi i for m=-1).
Verification
On , the exponential tail is bounded by the convergent numerical series , so the partial sums converge uniformly; division by preserves the bound because .
By [L2] and [L4], integrating the finite sum gives from the term and from every term.
Apply [L3] to the uniform convergence in step 1.1 and pass to the limit in step 1.2. The circle excludes , so division is defined.
Depends on
- The complex exponential by its power series
- The complex exponential series converges absolutely for every complex argument
- Complex line integrals are linear in the integrand
- A uniformly convergent sequence of continuous integrands on a fixed contour permits passage of the limit through the complex line integral
- On a positively oriented circle about a, the integral of (z-a)^m is zero for every integer m except -1, and is 2 pi i for m=-1
Used by
Nothing in the library uses this result yet.
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Sources
- L. Ahlfors, Complex Analysis, 3rd ed., Ch. 4, §1.3 (standard reference, not scraped)
- R. Howell and J. Mathews, Complex Analysis, §6.2 (standard reference, not scraped)