Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedverified 2026-09-23 (gpt-6-sol)
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Fejer summation of the square wave

Example

Let q be the one-periodic square wave defined by

q(x)={1,0<x<1/2,−1,−1/2<x<0,

with q(0)=q(1/2)=0. Then

σNq(x)=4π∑m=0⌊(N−1)/2⌋(1−2m+1N+1)sin⁡(2π(2m+1)x)2m+1,

and

σNq(0)→0.

Moreover ∣σNq(x)∣≤1 for every x and every N, so these positive means recover the midpoint value without a fixed Gibbs overshoot.

Facts & Assumptions

Given: The one-periodic square wave q above.

[L1]

The Cesaro means are defined by averaging Fourier partial sums (Cesaro and Abel means of a Fourier series).

[L2]

The Fejer kernels are nonnegative and have Riemann integral 1 (The Fejer kernel is a positive approximate identity).

Verification

technique · direct
1.1L1algebra

Direct integration gives q^(2m)=0 for every m and q^(2m+1)=2πi(2m+1),q^(−(2m+1))=−2πi(2m+1). Hence Sjq(x)=4π∑0≤m, 2m+1≤jsin⁡(2π(2m+1)x)2m+1.

2.1L1step 1.1algebra

Averaging the partial sums from step 1.1 as in [L1] shows that the odd mode 2m+1 appears with weight 1−(2m+1)/(N+1) when 2m+1≤N and with weight 0 otherwise. This is exactly the displayed formula for σNq.

3.1L1L2step 2.1algebra∎

Every term of the finite sine sum in step 2.1 vanishes at x=0, so σNq(0)=0 for every N. Also [L1] and [L2] give σNq(x)=∫01q(x−t)FN(t) dt, where the integral is Riemann because q is a step function. Since ∣q∣≤1, positivity and total mass one imply ∣σNq(x)∣≤1 for every x. Thus the Fejer means average across the jump and do not exhibit a fixed overshoot.

Depends on

Used by

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Dependency tree · two levels

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Sources