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Area defect of a hyperbolic geodesic triangle

Example

Assume the Axiom of Choice (The Axiom of Choice). In the upper-half-plane metric y−2(dx2+dy2) on H={y>0}, a compact geodesic triangle of area A has angle sum π−A; every such angle sum is therefore below π.

Here a compact geodesic triangle means a compact regular disk region in the sense of Regular oriented surface regions with corners, with exactly three distinct vertices and boundary the cyclic concatenation of three regular C2 embedded geodesic segments. At each vertex the incoming and outgoing one-sided unit tangents are not antipodal. Its angles are the interior sector angles, and its orientation is induced by dx∧dy. Thus degenerate collinear triples and ideal vertices are not included.

Facts & Assumptions

Given: The Axiom of Choice, the upper half-plane H={y>0} with the metric g=y−2(dx2+dy2), a compact geodesic triangle T⊆H in the regular disk-region sense specified above, of Riemannian area A, and the outward-normal-first orientation of ∂T.

[F1]

For an oriented Riemannian surface with a smooth positive orthonormal frame (E1,E2) on an open set and connection form ω(X)=g(∇XE1,E2), one has dω=−K dA, where K is the sectional curvature of the frame plane and dA the Riemannian volume form of the orientation (Gaussian curvature structure equation).

[F2]

In coordinates the Levi-Civita symbols of a Riemannian metric are Γkij=12∑ℓgkℓ(∂igjℓ+∂jgiℓ−∂ℓgij) (Christoffel formula for the levi civita connection).

[F3]

The Riemannian volume form of an oriented Riemannian manifold is the unique positive top form with dA(E1,…,En)=1 on every positive orthonormal frame; in particular for a positive orthonormal coframe (e1,e2) of a surface, dA=e1∧e2 (The riemannian volume form is the unique positive unit top form, Riemannian volume form on an oriented manifold).

[F4]

Under AC, for a positively oriented compact regular disk region with exactly three vertices whose boundary is the cyclic concatenation of three regular C2 geodesic segments with non-antipodal one-sided tangents and which lies in a frameable neighbourhood, ∫TK dA=α+β+γ−π, where α,β,γ are the interior sector angles (Gauss-Bonnet for a geodesic triangle).

[F5]

The Axiom of Choice is the choice-function principle (The Axiom of Choice). It licenses the AC-qualified geodesic formula used at step 2.2.

Verification

technique · exhibit a global positive orthonormal frame, compute its connection form and curvature by the structure equation, then insert $K\equiv-1$ into the geodesic-triangle formula
1.1given

On H oriented so that (∂x,∂y) is positive, the fields e1=y ∂x and e2=y ∂y are smooth and globally defined. Their Gram matrix is the identity because g(e1,e1)=y2⋅y−2=1, g(e2,e2)=y2⋅y−2=1 and g(e1,e2)=0; hence (e1,e2) is a global smooth positive orthonormal frame.

2.1F2step 1.1algebra

With gxx=gyy=y−2 and gxy=0, all x-derivatives of the coefficients vanish and ∂ygxx=∂ygyy=−2y−3. Formula [F2] gives Γxxy=Γxyx=12y2(−2y−3)=−1/y, Γyxx=12y2(2y−3)=1/y and Γyyy=12y2(−2y−3)=−1/y, while all remaining symbols vanish.

2.2F4F5step 1.1given

Let T be the supplied compact geodesic triangle of area A, regarded with the orientation induced from dx∧dy on H; its boundary receives the outward-normal-first orientation. Thus T is positively oriented relative to the ambient area form. By the disk-region hypothesis it is a compact regular oriented disk region with exactly three vertices, its sides are regular C2 geodesic segments with non-antipodal one-sided tangents, and the global frame of step 1.1 supplies a frameable neighbourhood. Under the assumed AC [F5], [F4] applies: ∫TK dA=α+β+γ−π for the interior sector angles.

3.1step 2.1algebra

The coordinate formulas of step 2.1 give ∇∂x∂x=(1/y)∂y and ∇∂y∂x=−(1/y)∂x. Since ∇e1e1=y ∇∂x(y∂x)=y((∂xy)∂x+y∇∂x∂x)=y ∂y=e2 and ∇e2e1=y ∇∂y(y∂x)=y((∂yy)∂x+y∇∂y∂x)=y(∂x−∂x)=0, the connection form satisfies ω(e1)=g(e2,e2)=1 and ω(e2)=0. Hence ω is the coframe element dual to e1, namely e1=dx/y.

4.1F3step 3.1algebra

Therefore dω=d(dx/y)=y−2 dx∧dy. The dual coframe is e1=dx/y and e2=dy/y, so e1∧e2=y−2 dx∧dy; by [F3] this is the Riemannian volume form dA of the chosen orientation, and dω=dA.

5.1F1step 1.1step 4.1algebra

The structure equation [F1] applied to the frame of step 1.1 gives dω=−K dA; with step 4.1 this forces K≡−1 on H. Consequently, for any positively oriented compact surface region T inside the frameable open set H, ∫TK dA=−∫TdA=−A.

6.1step 5.1step 2.2algebra∎

Substituting the value ∫TK dA=−A of step 5.1 into step 2.2 gives α+β+γ=π−A. The interior of a nonempty disk region is nonempty and the area form y−2dx∧dy is positive there, so A>0 and consequently α+β+γ<π: every such hyperbolic angle sum is a strict area defect of π.

Source locator

Lee, Riemannian Manifolds: An Introduction to Curvature, Chapter 9, printed pp. 156-172, works the constant-curvature examples through the local Gauss-Bonnet formula, and Datar, Lectures on Riemannian Geometry, Lecture 2, Theorem 2.0.1 together with the Poincare upper half-plane model, records the same computation. The Christoffel symbols are evaluated here from Christoffel formula for the levi civita connection on the explicit frame (y∂x,y∂y), and the curvature is read off from Gaussian curvature structure equation; the angle formula is Gauss-Bonnet for a geodesic triangle. No global result about hyperbolic geometry beyond this local computation is used.

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