Alphabeta Math
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Adequate observation time on a simple surface

Example

Assume Countable Choice. Let (M,g) be a compact, connected, nonempty simple two-dimensional Riemannian manifold with smooth boundary. Suppose L∗<∞ is an upper bound for the lengths of all maximal unit-speed geodesics in M. Let T>L∗ and let q1,q2∈Cc∞(M∘;R) be static interior potentials. If their full time-dependent Dirichlet-to-Neumann maps agree for every smooth boundary input compactly supported in (0,T)×∂M, then q1=q2 throughout M.

This gives a concrete observation-time condition: observing longer than a uniform upper bound on the maximal geodesic lengths suffices for coefficient uniqueness in the simple-surface case.

Facts & Assumptions

Given: Countable Choice; a simple compact Riemannian surface; a finite uniform upper bound L∗ on all maximal geodesic lengths; T>L∗; two real smooth interior potentials with equal full time-dependent DN maps.

[A1]

Countable Choice is the axiom base of the finite-time coefficient-uniqueness and two-dimensional X-ray injectivity suppliers. (The Axiom of Countable Choice (ACω))

[F1]

Under Countable Choice, on a compact connected nonempty simple surface, if L∗<∞ bounds all maximal unit-speed geodesic lengths and T>L∗, equality of the full forward DN maps on smooth time-compact boundary inputs implies q1=q2 for real static q1,q2∈Cc∞(M∘;R). The vanishing ray integrals are proved inside this corollary, not required as an additional premise. (Static wave coefficients are determined on a simple surface with adequate observation time)

[F2]

The unweighted scalar geodesic X-ray transform is injective on a compact simple surface. (Unweighted scalar geodesic X-ray injectivity on simple surfaces)

Proof

1.1given

By hypothesis, every maximal unit-speed geodesic has length at most L∗<T. Thus all maximal rays relevant to the finite-time coefficient-uniqueness corollary lie within the observation interval; the strict inequality also covers a ray attaining the upper bound.

2.1A1F1F2step 1.1given∎

Equal DN maps and the simple-surface hypotheses satisfy [F1]; since T>L∗, the corollary yields q1−q2=0 on M. Its X-ray injectivity step is justified by [F2], so q1=q2 as claimed.

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