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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
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Unweighted scalar geodesic X-ray injectivity on simple surfaces

Statement

Let (M,g) be a compact, connected, nonempty smooth Riemannian surface with smooth boundary. Write νout for its outward unit normal and use the curvature convention R(A,B)C=∇A∇BC−∇B∇AC−∇[A,B]C. Write DtJ=∇γ˙J; a Jacobi field along a unit-speed geodesic γ is a smooth field J satisfying Dt2J+R(J,γ˙)γ˙=0. Assume g(∇wνout,w)>0 for every nonzero boundary-tangent vector w, no nonzero Jacobi field on any positive-length unit-speed geodesic segment vanishes at both endpoints, and every maximal unit-speed geodesic starting in M∘ reaches ∂M in finite forward and backward time. Set SM={(x,v):x∈M, gx(v,v)=1} and ∂+SM={(x,v)∈SM:x∈∂M, gx(v,−νout)>0}. For a real-valued f∈Cc∞(M∘,R) and (x,v)∈∂+SM, let γx,v be the unit-speed geodesic with initial data (x,v), let τ+(x,v) be its first positive boundary-exit time, and define

I0f(x,v)=∫0τ+(x,v)f(γx,v(t)) dt.

Then I0f=0 on ∂+SM implies f=0 on M. No orientability assumption on M is required.

Facts & Assumptions

Given: A simple compact connected nonempty smooth Riemannian surface M, a real scalar f∈Cc∞(M∘), and zero boundary geodesic X-ray data I0f=0.

[F1]

Simple surface and geodesic X-ray transform: simple means strictly convex boundary, no conjugate points, and finite forward/backward exit times; I0f is the integral of f over each unit-speed boundary-to-boundary geodesic.

[F2]

The tangent orientation cover preserves simple-surface X-ray data: every connected component of the tangent orientation cover with pullback metric is compact, connected, oriented, and simple; its projection is a local isometry onto M.

[F3]

The tangent orientation cover preserves simple-surface X-ray data: I0,C(f∘π)(z~)=I0,Mf(π(z~)) for every incoming state z~ on a component C.

[F4]

Surface geodesic flow, index form, and transport primitive: zero scalar data gives a smooth compactly supported transport primitive u with Xu=−f and u∣∂SM=0; V is tangent to ∂SM.

[F5]

Pestov identity for geodesic data on a simple surface: for smooth real u vanishing on the boundary of an oriented simple surface, ∥VXu∥2=∥XVu∥2−(KVu,Vu)+∥Xu∥2.

[F6]

Surface geodesic flow, index form, and transport primitive: dΣ=dVg(x) dSx(v) and Santaló's formula is ∫SMh dΣ=∫∂+SMμ∫0τ+h(φt(z)) dt dΣ∂ for continuous h; Riemannian volume density: in coordinates dVg=det⁡Gx ∣dx1⋯dxn∣.

[F7]

Surface geodesic flow, index form, and transport primitive: Iγ(Y,Y)=∫0L(∣DtY∣2−g(R(Y,γ˙)γ˙,Y)) dt for endpoint-zero normal fields.

[F8]

Surface geodesic flow, index form, and transport primitive: the index form is positive for each nonzero endpoint-zero normal field.

[F9]

Fundamental theorem of riemannian geometry: the metric has a unique Levi-Civita connection.

[F10]

Levi civita connection: the Levi-Civita connection is metric-compatible and torsion-free.

[F11]

Curvature of an affine connection: R(A,B)C=∇A∇BC−∇B∇AC−∇[A,B]C.

[F12]

Riemann curvature four-tensor: Rm⁡(A,B,C,D)=g(R(A,B)C,D).

Proof

1.1F1F2F3F4given

If f=0, the conclusion holds; assume f≠0 for contradiction. Let C be any connected component of the tangent orientation cover of M and let f~=f∘π on C. By [F2], C is a compact oriented simple surface and I0,Cf~=0. The transport conclusion of [F4] supplies u∈Cc∞(SC∘) with Xu=−f~ and u=0 on ∂SC.

2.1F4F5step 1.1

The vector field V is vertical, so it differentiates functions along a fixed fibre and Vf~=0. Applying [F4] and [F5] to u gives 0=∥VXu∥2=∥XVu∥2−(KVu,Vu)+∥Xu∥2.

3.1F4F7F8F9F10F11F12step 1.1step 2.1

By [F4], Vu=0 on ∂SC: V is tangent to that boundary and u vanishes there. Fix any incoming unit geodesic γ:[0,L]→C, and let Q denote positive rotation by 90 degrees on each oriented tangent plane. In a positive orthonormal frame e1,e2=Qe1, metric compatibility gives ∇Ae1=ω(A)e2 and ∇Ae2=−ω(A)e1 for a scalar one-form ω. Using (∇AQ)ei=∇A(Qei)−Q∇Aei, we get (∇AQ)e1=−ω(A)e1+ω(A)e1=0 and (∇AQ)e2=−ω(A)e2+ω(A)e2=0, so ∇Q=0 and n(t)=Qγ˙(t) is a parallel unit normal. The scalar function w(t)=Vu(γ(t),γ˙(t)) has w(0)=w(L)=0, and put Y(t)=w(t)n(t); then ∣DtY∣2=(w′)2. The positive frame (γ˙,n) gives K=g(R(γ˙,n)n,γ˙). The curvature definition gives R(n,γ˙)=−R(γ˙,n); metric compatibility and the scalar commutator identity give 0=A(Bg(C,D))−B(Ag(C,D))−[A,B]g(C,D)=g(R(A,B)C,D)+g(C,R(A,B)D). Taking A=γ˙, B=n, C=γ˙, and D=n yields g(R(γ˙,n)γ˙,n)=−K, hence g(R(n,γ˙)γ˙,n)=K. Therefore ∫0L((XVu)2−K(Vu)2)(γ(t),γ˙(t)) dt=Iγ(Y,Y)≥0, with equality allowed only when Y=0, by [F8].

4.1F6step 3.1algebra

Apply Santaló's formula from [F6] to the continuous function (XVu)2−K(Vu)2 on SC. Step 3.1 shows that its integral over each boundary-to-boundary geodesic is nonnegative; the incoming flux weight is positive. Hence ∥XVu∥2−(KVu,Vu)=∫SC((XVu)2−K(Vu)2) dΣ≥0.

5.1F2F6step 1.1step 2.1step 4.1choose∎

Since Xu=−f~, the remaining term in step 2.1 is ∥Xu∥2=∥f~∥2. Under the standing assumption f≠0, choose an interior point x with f(x)≠0; continuity gives an open neighborhood on which f is nonzero. By [F2], π∣C is onto and a local diffeomorphism, so f~ is nonzero on a nonempty open subset of C; [F6] supplies a smooth positive Liouville density, making ∥f~∥2>0. This contradicts step 2.1 together with the nonnegative quantity in step 4.1. Therefore f=0.

Source locator

The source comparisons and item-specific dispositions are recorded in research/inverse-problems-knot-theory-all-109-2026-10-19-batch-38.coverage.json and the batch notes.

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