Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A smooth map with a local tangential cone neighborhood

Example

Let X=Y=R with their usual real Hilbert structure, let U=R, and define the smooth forward map F(t)=t+t2. At x†=1 the exact datum is y=F(1)=2. The local tangential cone condition holds at 1 on the closed ball of radius δ=1/4 with constant η=1/10.

Facts & Assumptions

Given: The standard real Hilbert line X=Y=R, U=R, F(t)=t+t2, x†=1, y=2, δ=1/4, and η=1/10.

[F1]

The one-coordinate Euclidean inner product is ⟨s,t⟩=st, with induced Euclidean norm (The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

[F3]

Every Cauchy sequence of real numbers converges, and a complete real inner-product space is a real Hilbert space (The reals are complete, Real and complex inner-product spaces and their induced length, Hilbert space).

[F4]

The Fréchet derivative is characterized by a remainder that is o(∥h∥) (Fréchet derivative between Banach spaces).

[F5]

The local TCC requires ∥F(x+h)−F(x)−F′(x)h∥≤η∥F(x+h)−F(x)∥ for every increment in its closed ball (Local tangential cone condition).

Verification

technique · direct
1.1givenF4algebra

For h∈R, F(1+h)−F(1)=3h+h2, so F(1+h)−F(1)−3h=h2. Since ∣h2∣/∣h∣=∣h∣→0, [F4] gives F′(1)h=3h; the polynomial is smooth.

2.1givenF1F2F3F5algebra∎

For ∣h∣≤1/4, the TCC remainder is ∣h∣2 and the data difference has magnitude ∣3h+h2∣=∣h∣∣3+h∣. If h≠0, then ∣3+h∣≥3−∣h∣≥11/4, so ∣h∣/∣3+h∣≤(1/4)/(11/4)=1/11<1/10. Thus ∣h∣2≤(1/10)∣3h+h2∣; for h=0 both sides vanish. Since B‾1/4(1)⊂R and F(1)=2, this verifies the stated local TCC neighborhood.

Depends on

Used by

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Dependency tree · two levels

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