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✓ 2 results · all verified · 2 also independently AI-judged
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Nonlinear maps and tangential cone control — Examples and Counterexamples

1 · Prerequisites

2 · Logical flowchart

3 · Definitions, theorems and proofs

None yet.

4 · Examples, counterexamples and false statements

CounterexampleConstruction: AI-generatedVerification: AI-generatedprecheck passjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)Open item page →

A smooth map can fail the tangential cone condition

Statement refuted

Every infinitely differentiable forward map between real Hilbert spaces satisfies a local tangential cone condition at each point of its domain with some radius δ>0 and some constant 0≤η<1.

Facts & Assumptions

Given: The standard real Hilbert line X=Y=R, the map F(t)=t2, basepoint x†=0, exact datum y=0, and a proposed local TCC radius δ>0 with constant 0≤η<1.

[F1]

The one-coordinate Euclidean inner product is ⟨s,t⟩=st, with induced Euclidean norm (The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

[F3]

Every Cauchy sequence of real numbers converges (The reals are complete).

[F4]

A real inner-product space complete in its induced norm is a real Hilbert space (Real and complex inner-product spaces and their induced length, Hilbert space).

[F5]

A Fréchet derivative is a bounded linear map whose remainder divided by the increment norm tends to zero (Fréchet derivative between Banach spaces).

[F6]

The local TCC at 0 would require ∣F(h)−F(0)−F′(0)h∣≤η∣F(h)−F(0)∣ whenever ∣h∣≤δ (Local tangential cone condition).

Counterexample

technique · direct
1.1givenF1F2F3F4F5constructalgebra

Identify R with the one-coordinate Euclidean space R1 by its sole coordinate; [F1] gives inner product st and [F2] gives norm ∣t∣. Every Cauchy sequence for this norm converges by [F3], so [F4] makes R a real Hilbert space. The polynomial F(t)=t2 is infinitely differentiable; moreover ∣F(h)−F(0)−0h∣/∣h∣=∣h∣→0 as h→0, so [F5] gives F′(0)=0.

2.1givenF6choosealgebra∎

Since δ>0, choose h=δ/2, which is nonzero and satisfies ∣h∣≤δ. Substitution in [F6] gives h2≤ηh2, hence 1≤η after division by h2>0, contradicting η<1. Therefore no such TCC radius and constant exist.

ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)Open item page →

A smooth map with a local tangential cone neighborhood

Example

Let X=Y=R with their usual real Hilbert structure, let U=R, and define the smooth forward map F(t)=t+t2. At x†=1 the exact datum is y=F(1)=2. The local tangential cone condition holds at 1 on the closed ball of radius δ=1/4 with constant η=1/10.

Facts & Assumptions

Given: The standard real Hilbert line X=Y=R, U=R, F(t)=t+t2, x†=1, y=2, δ=1/4, and η=1/10.

[F1]

The one-coordinate Euclidean inner product is ⟨s,t⟩=st, with induced Euclidean norm (The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

[F3]

Every Cauchy sequence of real numbers converges, and a complete real inner-product space is a real Hilbert space (The reals are complete, Real and complex inner-product spaces and their induced length, Hilbert space).

[F4]

The Fréchet derivative is characterized by a remainder that is o(∥h∥) (Fréchet derivative between Banach spaces).

[F5]

The local TCC requires ∥F(x+h)−F(x)−F′(x)h∥≤η∥F(x+h)−F(x)∥ for every increment in its closed ball (Local tangential cone condition).

Verification

technique · direct
1.1givenF4algebra

For h∈R, F(1+h)−F(1)=3h+h2, so F(1+h)−F(1)−3h=h2. Since ∣h2∣/∣h∣=∣h∣→0, [F4] gives F′(1)h=3h; the polynomial is smooth.

2.1givenF1F2F3F5algebra∎

For ∣h∣≤1/4, the TCC remainder is ∣h∣2 and the data difference has magnitude ∣3h+h2∣=∣h∣∣3+h∣. If h≠0, then ∣3+h∣≥3−∣h∣≥11/4, so ∣h∣/∣3+h∣≤(1/4)/(11/4)=1/11<1/10. Thus ∣h∣2≤(1/10)∣3h+h2∣; for h=0 both sides vanish. Since B‾1/4(1)⊂R and F(1)=2, this verifies the stated local TCC neighborhood.

Sources