Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-sol)audited 2026-09-30
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Jacobi fields in euclidean space

Example

For n≥0, give Rn its standard Euclidean metric gE=∑i=1ndxi⊗dxi. Let I⊆R be a nondegenerate interval, choose x,v∈Rn, and set γ(t)=x+tv. In the standard Cartesian trivialization, a smooth field J along γ is Jacobi if and only if there are constant vectors A,B∈Rn such that J(t)=A+tB(t∈I). This includes the constant geodesic v=0 and the zero-dimensional case n=0.

Facts & Assumptions

Given: The standard Euclidean metric on Rn, a nondegenerate interval I, and x,v∈Rn defining γ(t)=x+tv.

[F1]

The standard Euclidean inner product is ⟨u,w⟩=∑iuiwi, so its global Cartesian metric matrix is δij; a smooth symmetric positive-definite coordinate matrix defines a Riemannian metric (The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn, Coordinate criterion for a riemannian metric).

[F2]

In a smooth chart, the coordinate derivations ∂1∣p,…,∂n∣p form a basis of TpM (Coordinate derivations form a basis of the tangent space).

[F3]

The connection coefficients are defined by ∇∂i∂j=∑kΓkij∂k, and the Levi-Civita symbols satisfy Γkij=12∑ℓgkℓ(∂igjℓ+∂jgiℓ−∂ℓgij) (Christoffel symbols of an affine connection, Christoffel formula for the levi civita connection).

[F4]

In coordinates, Rℓkij=∂iΓℓjk−∂jΓℓik+ΓmjkΓℓim−ΓmikΓℓjm (Coordinate formula for the curvature tensor).

[F5]

A smooth curve is geodesic exactly when x¨k+Γkij(x)x˙ix˙j=0 in its coordinates (Coordinate geodesic equation).

[F6]

A smooth vector field along a smooth curve has smooth coefficient functions in a pulled-back frame (Vector field and section along a smooth curve).

[F7]

Along the curve, DtV=(γ∗∇)∂/∂tV and Dt(fV)=f′V+fDtV (Covariant derivative along a curve).

[F8]

The Jacobi equation is Dt2J+R(J,γ˙)γ˙=0 (Jacobi field).

[F11]

Every interval is order-convex, and a nondegenerate interval has at least two points (Intervals of R: the nine order-convex forms, nondegeneracy, and length).

Proof

technique · Cartesian coordinates and the componentwise Jacobi equation
1.1F1F3

In the global Cartesian chart, [F1] gives the constant metric matrix gij=δij, which is smooth, symmetric, and positive definite. All coordinate derivatives ∂igjℓ vanish, so [F3] gives Γkij=0 identically.

1.2F3F6F7step 1.1

Write an arbitrary smooth field as J(t)=∑iji(t)∂i∣γ(t) using [F6]. By the pullback-connection definition in [F7] and the Christoffel definition in [F3], Dt∂i=∑jγ˙j∇∂j∂i=∑j,kγ˙jΓkji∂k=0, because step 1.1 gives every Γkji=0. The product rule in [F7], applied twice, gives DtJ=∑iji′(t)∂i and Dt2J=∑iji′′(t)∂i.

2.1F2F4F5F8step 1.1step 1.2

The coordinate functions of γ are xi+tvi, hence γ¨i=0; [F5] and step 1.1 show that γ is an affinely parametrized geodesic. Substitution of Γ=0 and its zero derivatives into [F4] gives every curvature component zero; [F2] then gives R=0. By step 1.2 and [F8], the Jacobi equation is therefore ∑iji′′∂i=0, and [F2] implies ji′′=0 for every coordinate on the interior of I.

3.1F9F10F11step 2.1

For each i, the function ji′ is continuous on I and has derivative ji′′=0 at every interior point, so [F9] makes it a constant Bi. By [F10], the continuous function ji(t)−Bit has derivative ji′(t)−Bi=0 on the interior; another application of [F9] makes it a constant Ai. Thus ji(t)=Ai+tBi throughout I, including any endpoints by continuity, and the component vectors give J(t)=A+tB.

3.2F7F8step 1.1step 1.2step 2.1

Conversely, for any constant A,B∈Rn, the field J(t)=A+tB is smooth. Steps 1.1–1.2 and [F7] give DtJ=B in the constant coordinate frame, Dt2J=0, and step 2.1 gives R=0; [F8] therefore makes J Jacobi.

4.1F2F6F7F8F11step 1.2step 2.1step 3.1step 3.2∎

If n=0, the tangent spaces and field contain only zero, represented by the unique A=B=0; if n=1, the same component calculation is scalar. The case v=0 is included because step 2.1 still gives a constant geodesic and step 1.2 allows arbitrary smooth coefficient functions; A=0, B=0, or J=0 need no exclusion. At included time endpoints all derivatives are one-sided and the affine formula extends by continuity. Only finitely many coordinates are considered, and the proof makes no choice; singleton intervals are excluded by the nondegeneracy hypothesis. Steps 2.1, 3.1 and 3.2 prove both directions of the stated classification.

Source locator

Lee, Riemannian Manifolds: An Introduction to Curvature, Chapter 5, “Geodesics of the Model Spaces—Euclidean Space,” printed p.81 / PDF labels P97–98, lines 3393–3399, states that the Euclidean metric has constant coefficients, its Christoffel symbols vanish, and its geodesics are straight lines. Datar, Lectures on Riemannian Geometry, Lecture 22, Example 22.1.1, printed p.160 / PDF label P167, lines 9120–9128, states the component equation J′′=0 and the affine solution form but does not derive them; the proof above supplies that calculation. Datar's immediately following statement that every nonzero Jacobi field “has a unique zero” is not used: a nonzero constant affine field has no zero, and in general the valid conclusion is at most one zero.

Depends on

Used by

Dependency tree · two levels

64 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources