Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
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An Lp-bounded martingale with an Lp terminal value

Statement

Assume AC. If p>1, X∈Lp, (Fn) is a filtration, and F∞ is a sigma-algebra containing every Fn, then Mn=E[X∣Fn] is Lp-bounded and converges almost surely and in Lp to an F∞-measurable M∞. If F∞=σ(⋃nFn), then M∞=E[X∣F∞].

Facts & Assumptions

Given: The hypotheses, objects, and conventions in the Statement.

[F1]

Conditional expectation process is a martingale makes (Mn) a martingale.

[F2]

Conditional lp contraction gives ∥Mn∥p≤∥X∥p.

[F3]

Lp-bounded martingale convergence gives almost-sure and Lp convergence.

[F4]

Levy upward convergence of conditional expectations identifies the generated-σ-algebra limit.

[F5]

The Axiom of Choice states AC, assumed here because F1--F4 use conditional expectations and chosen representatives.

Proof

1.1F1F2F3

F1 makes (Mn) a martingale, and F2 gives sup⁡n∥Mn∥p≤∥X∥p<∞. F3 therefore supplies M∞∈Lp with both asserted modes of convergence. As a pointwise limit of variables measurable for F∞, it has an F∞-measurable version.

2.1F4F5step 1.1∎

When F∞=σ(⋃nFn), F4 gives almost-sure and L1 convergence of the same sequence to E[X∣F∞]. Limits in probability are unique, so it equals the Lp limit M∞ almost surely. AC is used exactly through F5.

Depends on

Used by

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Dependency tree · two levels

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Sources