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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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These labels describe origin, not correctness: citations and verification chips remain separate evidence.

One-surgery on a three-manifold as framed knot surgery

Example

Assume ACω, as in the surgery definition. For a framed knot in a closed oriented 3-manifold, 1-surgery replaces S1×int⁡D2 by D2×S1, with the boundary identification fixed by the framing.

For the unknot use S3=∂(Dx2×Dy2) with compatible corner rounding, decomposed into U=Sx1×Dy2 and V=Dx2×Sy1. The core is Sx1×{0}⊂U. Its framing with integer twist k is the actual product embedding φk(x,z)=(x,xkz) into U. Zero twist produces S2×S1; one twist produces S3. Their fundamental groups are Z and 0, so these are different results for the same underlying knot. A bare swap of the two boundary circles is not a framing change: it exchanges the meridian with a longitude and does not extend over the removed solid torus.

Verification

Given: the unknot core in U, and the framed embeddings φ0 and φ1; circle coordinates are complex numbers of modulus one.

[F1] p-surgery on a smooth m-manifold specifies the gluing by the framed product embedding on the boundary torus.

[F2] The outgoing boundary of a handle attachment trades the disk factors gives ∂(D2×D2)=(S1×D2)∪(D2×S1), with handle parameters k=2, n=4.

[F4] A diffeomorphism and its inverse give inverse induced maps on loop classes by composition (The homomorphism on fundamental groups induced by a pointed continuous map), so distinct fundamental groups rule out diffeomorphism.

1.1F1givenconstruct

Each φk is a smooth embedding with inverse (x,y)↦(x,x−ky) on U, and all have core S1×{0}. Writing the replacement torus as T=Da2×Sb1, its boundary gluing to V is gk(a,b)=(a,akb). This follows directly from [F1], using a as the attaching-sphere coordinate and b as the normal-circle coordinate.

2.1F1step 1.1algebra

For k=0, g0 is the product identification. Thus V∪g0T=(D2∪S1D2)×S1≅S2×S1. To check smoothness of the disk double identification, map polar disk coordinates (r,u) in the two copies to (sin⁡(πr/2)u,±cos⁡(πr/2)) on S2; it is smooth and invertible at the centres and in the signed collar coordinate at the seam.

2.2F1F2step 1.1constructalgebra

For k=1, change coordinates by diffeomorphisms of the solid tori themselves: L:V→V, L(x,y)=(xy−1,y), and R:T→T, R(a,b)=(ab−1,b). The transformed boundary gluing is L∘g1∘R(a,b)=(b−1,a), as direct multiplication shows. This exchanges the two boundary circle factors with one reversal. In the boundary decomposition of [F2], identify the first solid torus S1×D2 with T=D2×S1 by (a,b)↦(b−1,a); it is a diffeomorphism, so the transformed gluing produces the boundary of D2×D2. A convex corner rounding is radially transverse to all rays from the origin; write its boundary as ρ(u)u for smooth positive ρ on S3. The radial map and its inverse z↦z/∣z∣ prove that boundary is diffeomorphic to S3. Hence one-twist surgery gives S3.

3.1F3F4step 2.1step 2.2∎

By [F3] and [F4], the manifolds computed in steps 2.1 and 2.2 cannot be diffeomorphic. These two valid framings of the same core knot therefore give different diffeomorphism types.

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