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ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Ordinary and self-normalized importance sampling on a two-point space

Example

Let X={a,b} with counting measure, unnormalized target density p~(a)=p~(b)=1, proposal probabilities Q(a)=3/4 and Q(b)=1/4, and integrand f=1{b}. Then Zp=2, the target probabilities are π(a)=π(b)=1/2, and θ=∫f dπ=1/2. The proposal has full target support.

Facts & Assumptions

Given: The finite space, target, proposal, integrand, and normalizer in the Example.

[F1]

Ordinary importance sampling: For each proposal draw, ordinary importance sampling uses Yi=f(Xi)p~(Xi)/(Zpq(Xi)) and returns their sample mean.

[F2]

Self-normalized importance sampling: When the sum of the nonnegative weights Wi=p~(Xi)/q(Xi) is positive, the self-normalized estimate is ∑iWif(Xi)/∑iWi.

[F3]

Ordinary importance sampling is unbiased: Under the stated support and integrability assumptions, the ordinary importance sampling estimate has expectation ∫f dπ.

Verification

Given: Use one proposal draw X∼Q and the definitions in [F1] and [F2].

1.1givenF3algebra

The target normalizer is Zp=p~(a)+p~(b)=2, so π(a)=π(b)=1/2 and θ=Eπf=1/2. Since both proposal probabilities are positive and X is finite, the support and integrability assumptions of [F3] hold.

2.1F1F3step 1.1algebra

The ordinary weighted value is 0 at a and 2 at b. Its expectation is (3/4)0+(1/4)2=1/2=θ, as also guaranteed by [F3].

3.1F2step 1.1algebra∎

The self-normalized weights are 4/3 at a and 4 at b, so the single-draw ratio in [F2] equals f(X). Its expectation is Q(X=b)=1/4, and its bias for θ is 1/4−1/2=−1/4. This verifies that self-normalization need not be unbiased at finite sample size.

Depends on

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