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A rational half-rotation has a nonconstant ergodic limit
Example
Assume the Axiom of Countable Choice. For on the circle and , the averages converge at every point to
a nonconstant invariant function.
Facts & Assumptions
Given: Countable choice, Lebesgue probability on the circle, , and .
The half-rotation preserves Lebesgue probability (Circle rotations preserve Lebesgue measure).
The average is (Ergodic partial sums, time averages, and the invariant L2 subspace).
Half-open intervals have Lebesgue measure equal to their length (A box in with parameters is Lebesgue measurable of measure , whichever of its faces are included).
Countable choice is the standing assumption required by the circle-measure and interval-measure suppliers (The Axiom of Countable Choice ()).
Verification
Since is the identity, the summands alternate between and . Moreover .
For , . For , the counts of the two summands differ by one, so pointwise.
It follows that at every point. The half-rotation interchanges the two support intervals, so ; by [F3] it takes both values and on sets of positive measure and is therefore nonconstant.
Finally, [F3] gives . Thus the limit preserves the mean but need not equal the constant mean in this nonergodic example. Countable choice is used only through [F1] and [F3].
Depends on
- Ergodic partial sums, time averages, and the invariant L2 subspace
- Circle rotations preserve Lebesgue measure
- A box in $\mathbb{R}^n$ with parameters $a_i\le b_i$ is Lebesgue measurable of measure $\prod_{i<n}(b_i-a_i)$, whichever of its faces are included
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
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Sources
- Charles Walkden, Ergodic Theory lecture notes (standard reference, not scraped)