Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedaudited 2026-09-14
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A rational half-rotation has a nonconstant ergodic limit

Example

Assume the Axiom of Countable Choice. For T=R1/2 on the circle and f=1[0,1/4), the averages converge at every point to

g=121[0,1/4)[1/2,3/4),

a nonconstant invariant function.

Facts & Assumptions

Given: Countable choice, Lebesgue probability on the circle, T=R1/2, and f=1[0,1/4).

[F1]

The half-rotation preserves Lebesgue probability (Circle rotations preserve Lebesgue measure).

[F2]

The average is Anf=n1k<nfTk (Ergodic partial sums, time averages, and the invariant L2 subspace).

[F4]

Countable choice is the standing assumption required by the circle-measure and interval-measure suppliers (The Axiom of Countable Choice (ACω)).

Verification

technique · direct period-two calculation
1.1

Since T2 is the identity, the summands alternate between f and fT. Moreover fT=1[1/2,3/4).

givenalgebra
2.1

For n=2q, Anf=(f+fT)/2=g. For n=2q+1, the counts of the two summands differ by one, so Anfg1/n pointwise.

F2step 1.1
3.1

It follows that Anfg at every point. The half-rotation interchanges the two support intervals, so gT=g; by [F3] it takes both values 0 and 1/2 on sets of positive measure and is therefore nonconstant.

F1F3step 1.1step 2.1
4.1

Finally, [F3] gives gdλ=(1/2)(1/4+1/4)=1/4=fdλ. Thus the limit preserves the mean but need not equal the constant mean in this nonergodic example. Countable choice is used only through [F1] and [F3].

F1F3F4step 3.1algebra

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