Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedprecheck passaudited 2026-10-02
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A regular hyperplane has a one-sheeted projection

Example

Assume the Axiom of Choice (The Axiom of Choice). Fix n≥1 and let

X={z∈Cn:zn=0}

be the coordinate hyperplane through the origin. Then zn is a reduced equation of the hypersurface germ X with dzn≠0 everywhere, so every point of X is regular; the projection π(z)=z′=(z1,…,zn−1) is one-sheeted with constant discriminant 1 and empty branch set; and dim⁡0X=n−1. The Axiom of Choice is used only through the numerical dimension result [F7] for holomorphic germ rings below.

Facts & Assumptions

Given: An integer n≥1, the coordinate hyperplane X={zn=0}⊆Cn, its equation germ zn∈OCn,0, and the projection π(z)=z′ forgetting the last coordinate.

[F1]

A hypersurface germ at 0 is the zero germ of a nonzero nonunit; its reduced defining germ is unique up to a unit (Complex-analytic hypersurface germ and its reduced equation).

[F2]

A reduced germ is a nonzero nonunit that is not divisible by the square of an irreducible germ; irreducible means not a product of two nonunits, and an irreducible germ is reduced (Reduced holomorphic germ for a hypersurface, Irreducible and prime elements of an integral domain).

[F3]

A Weierstrass polynomial of degree 1 in the last variable has the form zn+a0(z′) with a0∈OCn−1,0, a0(0)=0; in particular zn itself is a degree-one Weierstrass polynomial and W(0,zn)=zn (Weierstrass polynomials in the last variable).

[F4]

A point q of a reduced hypersurface germ is regular exactly when the differential of a local reduced equation at q is nonzero, equivalently exactly when the germ is a holomorphic hypersurface graph near q (Regular and singular points of an analytic hypersurface).

[F5]

The discriminant of a monic degree-one polynomial t+a1 is 1; in particular Disc⁡zn(zn)=1≠0 (The discriminant of a monic polynomial as the coefficient expression of Δn2).

[F6]

For a prepared equation W on the chosen product neighbourhood V×D of the finite projection theorem, containing all slice roots in D and none on ∂D, put XW:=Z(W)∩(V×D) and let πW:XW→V be the restricted coordinate projection. The discriminant definition and finite projection theorem give DW=Disc⁡(W), branch set BπW={DW=0}⊆V, and a proper surjection with finite fibres that is a covering with as many sheets as the degree of W over V∖BπW; when n=1 the base is a single point (Discriminant and branch set of a fixed Weierstrass projection, Finite local projection of a reduced hypersurface germ).

[F7]

Assume the Axiom of Choice. For m≥0 the Krull dimension of the holomorphic germ ring is dim⁡OCm,0=m, with OC0,0=C; this is the only place where the Axiom of Choice is used in the present example (Krull dimension of the holomorphic germ ring, The Axiom of Choice).

[F8]

The local dimension of a hypersurface germ is dim⁡0X=dim⁡OCn,0/(fred) for any reduced equation fred of X (Local Krull dimension of a hypersurface germ).

[F9]

A germ h∈OCn,0 expands as a convergent power series in zn with coefficients hk∈OCn−1,0, so h−h0∈(zn) and the substitution zn=0 induces an isomorphism OCn,0/(zn)→OCn−1,0, h+(zn)↦h(z′,0) (A continuous separately holomorphic function is the sum of an absolutely convergent power series with Cauchy-integral coefficients on every smaller polydisc).

Proof technique: direct — identify the reduced equation, compute the gradient and the discriminant, and compute the local ring by expanding in the last variable.

Verification

1.1givenF1F2

The germ zn is irreducible: if zn=ab with a,b nonunits, then a,b∈m0 and hence zn=ab∈m02, contradicting that zn∉m02 because its linear part is nonzero. By [F2] zn is therefore reduced, and X=Z(zn) is a hypersurface germ whose reduced defining germ is zn by [F1], with Z(zn) exactly the hyperplane {zn=0}.

2.1step 1.1F4construct

Every point q∈X is regular. Indeed X={zn=0} is the graph of the zero function over the z′-coordinates near q, so by the graph criterion of [F4] q is regular; equivalently, dzn≠0 everywhere and the reduced local equation zn has nonvanishing differential at q.

2.2step 1.1F3F5F6

For the prepared equation W=zn of degree 1 in the last variable, [F3] and [F5] give DW=Disc⁡zn(zn)=1≠0. On the product representative V×D, [F6] gives the local branch set BπW={DW=0}=∅ and the one-sheeted covering πW:XW→V, where XW=Z(W)∩(V×D)={(z′,0):z′∈V}. Separately, the global coordinate projection π:X→Cn−1 is the identity under the identification X={zn=0}≅Cn−1, so it is a one-sheeted covering over its whole base; the local map above is its restriction to XW. When n=1 both bases are the single point z′=0.

3.1step 1.1step 2.2F8F9F7

For the same prepared equation W=zn as in step 2.2, the expansion [F9] in the last variable shows that the substitution zn=0 gives a ring isomorphism OCn,0/(zn)≅OCn−1,0; combined with the definition of local dimension in [F8] this gives dim⁡0X=dim⁡OCn−1,0=n−1, where the numerical value is the dimension result [F7], the only use of the Axiom of Choice.

4.1step 2.1step 2.2step 3.1∎

Assembling steps 2.1, 2.2 and 3.1: the hyperplane germ X={zn=0} has the reduced equation zn with nonzero differential everywhere, its projection to z′ is one-sheeted with discriminant 1 and branch set ∅, and dim⁡0X=n−1. At n=1 the curve is the point germ {0}⊆C, the base is a point, and the dimension is 0=1−1, so the degenerate case is covered.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

71 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources