Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Locally constant functions form a sheaf and have constant stalks

Example

Fix a set A. For each open set U⊆X, let A‾loc(U):={f:U→A locally constant}. With the usual restriction maps, this is a sheaf of sets on X. For every x∈X, evaluation at x induces a canonical bijection A‾loc,x≅A.

Facts & Assumptions

Given: A set A, an open set U⊆X, and a point x∈X.

[L1]

The sheaf condition is locality and unique gluing on open covers (A sheaf on a topological space).

[F1]

The stalk at x is the colimit of sections on neighbourhoods of x (The stalk of a presheaf at a point).

[F2]

The germ of a section is its class in that stalk (Germs of sections).

Verification

technique · direct
1.1L1givenconstruct

Restriction preserves local constancy. If two locally constant functions on U agree on an open cover, then they agree pointwise on U. If locally constant functions fi:Ui→A are compatible on an open cover of U, the pointwise glued function f is well defined and locally constant because near any point it agrees with one of the local functions fi. Hence [L1] holds and A‾loc is a sheaf.

2.1F1F2given∎

Define ϵx:A‾loc,x→A by ϵx([U,f])=f(x). This is well defined because equal germs agree on some neighbourhood of x, hence have the same value at x. Every a∈A is the value at x of the constant function a on any neighbourhood of x, so ϵx is surjective. If ϵx([U,f])=ϵx([V,g]), then f(x)=g(x). Since both functions are locally constant, there is a neighbourhood W of x on which f and g are both constantly this common value, so [U,f]=[V,g]. Therefore ϵx is bijective.

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources