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A smooth scattered surface inherits the Matérn fill-distance rate

Example

Assume the Axiom of Choice and Countable Choice as required by the Fourier-space and interpolation suppliers. Fix d≥1, ν>0, a>0, and let Ω=(0,1)d. The smooth graph {(x,f(x)):x∈Ω‾} with f(x)=e−π∣x∣2 is interpolated from midpoint-grid samples by the normalized Matérn kernel of smoothness ν.

Facts & Assumptions

Given: Full AC, Countable Choice, the fixed d,ν,a, the cube, the function f, and midpoint grids Xm={(i1+1/2m,…,id+1/2m):0≤ij<m},m∈N,m≥1.

[F1]

An admitted domain is nonempty, bounded and Lipschitz and has a single cone radius and aperture at every point of the closure; the fill distance is hX=sup⁡x∈Ωmin⁡y∈X∣x−y∣. (Radial kernels, polynomial augmentation, and site geometry)

[F2]

Every Schwartz function is in the Fourier Bessel-potential space Hs(Rd) for every s>d/2, and Hs(Ω) consists of restrictions of whole-space members. (Schwartz functions are dense in the Fourier Bessel-potential norm, Fourier Bessel-potential and restriction-quotient Sobolev spaces)

[F4]

The Schwartz seminorms require polynomially weighted derivatives to be bounded. For any degree M≥0, take an integer n≥1 with 2n≥M; for r≥1, rM≤r2n and exponential domination applied with x=r2 gives r2ne−πr2→0. On ∣x∣≤1, each polynomial is bounded by the sum of the absolute values of its finitely many coefficients. (Schwartz space and its seminorms, The exponential dominates every fixed nonnegative integer power at +∞)

[F5]

The Matérn interpolation error and power function are bounded by ChXν on an admitted cone domain for small fill distance. (Matérn interpolation and its power function converge at rate h^ν)

Proof technique: verify the domain, regularity, and grid radius, then apply the fill-distance theorem.

Verification

technique · verify the domain, regularity, and grid radius, then apply the fill-distance theorem

Given: The data above.

1.1F1givenconstructalgebra

The cube is bounded and Lipschitz. At a boundary point p, let I be the nonempty set of active coordinates (pj=0 or 1), with inward signs σj=1 at 0 and −1 at 1. Put uj=σj/∣I∣ for j∈I and uj=0 otherwise. In the orthogonal coordinates x=p+y+tu with y⊥u, a sufficiently small neighborhood has no constraints from inactive coordinates, and the active inequalities reduce to t>max⁡j∈I(−∣I∣ σjyj). This is the epigraph of a finite maximum of linear functions, hence a local Lipschitz graph with the cube on one side. The cube also satisfies the uniform cone condition: for x∈[0,1]d, let σj=1 if xj≤1/2 and σj=−1 otherwise, and put u=(σ1,…,σd)/d. If u=e1 let Qx=I; otherwise put v=(e1−u)/∣e1−u∣ and Qx=I−2vvT, which is orthogonal and sends e1 to u. Choose 0<θ<π/2 with cos⁡θ/d−sin⁡θ>0, and set r0=1/2. For any cone vector z, z1>∣z∣cos⁡θ and ∣z−z1e1∣<∣z∣sin⁡θ. Hence for every coordinate, σj(Qxz)j≥z1/d−∣z−z1e1∣>∣z∣(cos⁡θ/d−sin⁡θ)>0. Each coordinate moves toward the cube's interior by less than r0, so x+Qxz∈(0,1)d.

2.1F2F3F4step 1.1algebra

The sites in Xm are distinct. Each x∈(0,1)d is at coordinatewise distance at most 1/(2m) from a midpoint in each grid interval, so hXm≤d/(2m)→0. By [F3], every partial derivative of f is a finite sum of polynomial multiples of e−π∣x∣2; [F4] makes every polynomially weighted derivative bounded, so f is Schwartz. Then [F2] gives f∣Ω∈Hs(Ω) for s=ν+d/2.

3.1F5step 2.1algebra∎

For all sufficiently large m, step 2.1 gives hXm≤h0 from [F5]. The Matérn interpolation theorem therefore yields ∥f−sXmf∥L∞(Ω)≤ChXmν∥f∥Hs(Ω)≤C(d2m)ν∥f∥Hs(Ω),sup⁡x∈ΩPXm(x)≤C(d2m)ν. The graph samples are the scattered surface data, and the bound uses fill distance alone; no mesh-ratio condition is needed.

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