Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedaudited 2026-09-10
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Strong law for empirical indicator averages

Example

For IID random elements (Xn) and a fixed measurable A, n1kn1A(Xk)P(X1A) almost surely. A single conull event works for any specified countable class of sets A.

Facts & Assumptions

[F1]

Measurable coordinatewise functions preserve independence: Let (Xi)iI be an independent family of random elements Xi:(Ω,F,P)(Si,Σi). For each i, let gi:(Si,Σi)(Ti,Ti) be measurable. Then the family (giXi)iI is independent.

[F2]

The expectation of an indicator is the probability of the event: Let (Ω,F,P) be a probability space and let AF. Then the indicator 1A satisfies E[1A]=P(A).

[F3]

Kolmogorov iid l1 strong law: For IID real (Xn)n1 with EX1<, Sn/nμ=EX1 almost surely.

[F4]

Finite and countable subadditivity of measures: Let μ be a measure and let (Ek)kN be measurable. Then

μ(kNEk)k=0μ(Ek).

For every mN one also has

μ(k<mEk)k<mμ(Ek),

including m=0, where both sides are 0.

Verification

Given: The objects, hypotheses and definitions in the statement. Its conclusions are to be established below.

1.1

The measurable maps x1A(x) take values in {0,1}. F1 preserves the IID property, and F2 computes their expectation as pA=P(X1A); their absolute expectations are at most one.

F1F2
2.1

F3 applied to step 1.1 gives the fixed-set limit. For a specified countable class, let N_A be the failure event for that limit. F4 gives P(ANA)A0=0. Outside this union every stated frequency converges simultaneously.

F3F4step 1.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

20 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources