Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedverified 2026-09-23 (gpt-6-sol)
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The angular period and the obstruction to bounding

Example

Assume countable choice ACω. On R2∖{0} let ω=−y dx+x dyx2+y2. Its integral over the counterclockwise unit circle is 2π. Therefore that circle cannot be the induced oriented boundary of a compact oriented embedded smooth surface contained in the punctured plane; the form is also not exact there.

Facts & Assumptions

[A1]

Countable choice is The Axiom of Countable Choice (ACω); it is used for the global Stokes and embedded-submanifold integration route in [F1].

[F1]

A nonzero period obstructs exactness and bounding: Under ACω, if S↪M is an oriented compact boundaryless embedded k-submanifold, k≥1, and ω is a closed smooth k-form on M with ∫Sω≠0, then ω is not exact on M and S cannot be the induced oriented boundary of a compact embedded (k+1)-submanifold of M.

[F2]

Computing form integrals by finite parametrizations: Let n≥1, let Mn be oriented, and let ω∈Ωcn(M). For 1≤i≤m let Di⊂Rn be bounded open Jordan domains and Fi:D‾i→M continuous and smooth up to the boundary in target coordinates: near each parameter point, a target coordinate representative extends smoothly to a Euclidean neighborhood. Suppose Fi∣Di is an orientation-preserving diffeomorphism onto an open Wi⊂M, the Wi are pairwise disjoint, and supp⁡ω⊂⋃iW‾i. Then ∫Mω=∑i=1m∫DiFi∗ω. An empty family is allowed when the support is empty. No nonsingularity of DFi on ∂Di, and no M-valued extension across a genuine target boundary, is assumed.

Verification

Given: ACω and the objects and hypotheses in the statement above.

1.1algebra

Write P=−y/(x2+y2) and Q=x/(x2+y2). Direct differentiation gives Qx=(y2−x2)/(x2+y2)2=Py, hence dω=0 on the punctured plane. The origin is excluded from its domain.

1.2F2

For c(t)=(cos⁡t,sin⁡t), c∗ω=dt. The interval (0,2π) maps diffeomorphically to the circle minus one point and extends smoothly to its closure. The finite-parametrization formula gives ∫S1ω=2π.

2.1A1F1step 1.1step 1.2∎

The circle is compact, embedded, oriented, and boundaryless, with dimension one. Its nonzero period and the closedness calculation meet all hypotheses of the period obstruction, giving both nonexactness and the stated nonbounding conclusion under [A1].

Depends on

Used by

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Sources