Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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Volume-form divergence on the Euclidean ball

Example

For the closed unit ball B3 oriented by dxdydz, the field F=(x,y,z) has divergence 3 and outward flux 4π. The field G=(x,0,0) has divergence 1 and outward flux 4π/3. In each case the volume integral equals the flux.

Facts & Assumptions

[F1]

Agreement with classical Gauss flux in Euclidean space: For μ=dxdydz and a smooth Euclidean field F, the volume-form divergence is xFx+yFy+zFz. For a surface parametrization r(u,v), r(ιFμ)=(F(r)(ru×rv))dudv. Consequently the volume-form divergence theorem agrees with the classical Gauss flux theorem on compact smooth regions that also admit the supplied elementary-solid presentation required by that classical theorem.

[F2]

Computing form integrals by finite parametrizations: Let n1, let Mn be oriented, and let ωΩcn(M). For 1im let DiRn be bounded open Jordan domains and Fi:DiM continuous and smooth up to the boundary in target coordinates: near each parameter point, a target coordinate representative extends smoothly to a Euclidean neighborhood. Suppose FiDi is an orientation-preserving diffeomorphism onto an open WiM, the Wi are pairwise disjoint, and suppωiWi. Then Mω=i=1mDiFiω. An empty family is allowed when the support is empty. No nonsingularity of DFi on Di, and no M-valued extension across a genuine target boundary, is assumed.

Verification

Given: The objects and hypotheses in the statement above.

1.1

Use R(r,ϕ,θ)=(rsinϕcosθ,rsinϕsinθ,rcosϕ) on (0,1)×(0,π)×(0,2π). Its determinant is r2sinϕ>0, it is a diffeomorphism onto its open image and extends smoothly in coordinates from the closed box. The missing radial cut and axes lie in the image of its parameter boundary. Finite parametrizations give VolB3=01r2dr0πsinϕdϕ02πdθ=4π/3.

F2
2.1

For the sphere parametrization q=R(1,ϕ,θ), qϕ×qθ=sinϕq, which points outward for 0<ϕ<π. Thus F has flux integrand sinϕ, whose double integral is 4π; its volume divergence integral is 3(4π/3)=4π.

F1F2step 1.1
3.1

For G the flux integrand is qx2sinϕ=sin3ϕcos2θ. The two factors integrate to 4/3 and π, giving 4π/3. The first value follows from u=cosϕ, and the second from cos2θ=(1+cos2θ)/2. Divergence is one, so its volume integral agrees. The poles and seam are parameter-boundary images handled by the finite-parametrization formula.

F1F2step 1.1step 2.1

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