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PropositionStatement: AI-adaptedProof: AI-adaptedPipeline-generatedaudited 2026-09-07
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Agreement with classical Gauss flux in Euclidean space

Statement

Let F be a smooth vector field on an open subset OR3 and let μ=dxdydz. Then the volume-form divergence is xFx+yFy+zFz. For a smooth surface parametrization r(u,v) with image in O (and pointwise also for a C1 parametrization), r(ιFμ)=(F(r)(ru×rv))dudv. Assuming ACω, consequently the volume-form divergence theorem agrees with the classical Gauss flux theorem on every compact smooth region EO, oriented by μ, supplied with the elementary-solid presentation required by that classical theorem. Here a smooth region is an embedded three-dimensional manifold with boundary and its usual induced smooth structure; the same field is defined on the open neighborhood O of all of E.

Facts & Assumptions

[F1]

Divergence theorem for a volume form: Assume ACω. Let Mn be oriented with boundary, n1, let μ be a positive smooth volume form, and let X be a compactly supported smooth vector field. Then M(divμX)μ=Mj(ιXμ), with outward-normal-first orientation. For compact M every smooth X is allowed.

[F2]

Computing form integrals by finite parametrizations: Let n1, let Mn be oriented, and let ωΩcn(M). For 1im let DiRn be bounded open Jordan domains and Fi:DiM continuous and smooth up to the boundary in target coordinates: near each parameter point, a target coordinate representative extends smoothly to a Euclidean neighborhood. Suppose FiDi is an orientation-preserving diffeomorphism onto an open WiM, the Wi are pairwise disjoint, and suppωiWi. Then Mω=i=1mDiFiω. An empty family is allowed when the support is empty. No nonsingularity of DFi on Di, and no M-valued extension across a genuine target boundary, is assumed.

[F3]

The divergence theorem on an elementary solid region: Let E be an elementary solid region with presentation Σ=((D1,φ1),,(DP,φP)) (def-elementary-solid-region) and let F be a C1 vector field on an open set containing E. Then EdivF=EF,n, where the left side is the integral of divF over E and the right side is the flux of F over the presentation Σ, that is j=1PDjF(φj),φj,u×φj,v. At every interior parameter point whose projection lies in the interior of the relevant base, the orientation in which that flux is taken is the outward one, by cor-every-face-of-an-elementary-solid-region-is-outward-oriented.

[F4]

Unit normal fields, orientations, and flux through a regular surface patch: For a regular patch (D,φ), the parametrization induces on its interior the unit normal Nφ=φu×φvφu×φv2. The denominator is positive there by regularity and thm-surface-area-density-is-cross-product-norm, and the vector is orthogonal to the tangent plane (def-tangent-plane-of-a-regular-surface-patch). Choosing Nφ rather than Nφ is an orientation. For a continuous vector field F, the flux in the orientation induced by φ is D(Fφ)(φu×φv). This is the scalar Riemann integral of a continuous function on D (def-surface-area-and-scalar-surface-integral-of-a-patch, def-euclidean-inner-product); replacing the orientation by its negative negates the integrand.

[F5]

Divergence as an exterior derivative: For a positive volume form μ and smooth vector field X on an oriented smooth n-manifold, n1, with boundary allowed, d(ιXμ)=(divμX)μ. No tangency assumption on X at the boundary is needed.

[F6]

Simple solid regions in a coordinate direction and their cyclic coordinate projection: A simple description gives a compact Jordan measurable solid E. In particular, the supplied simple descriptions in an elementary-solid presentation make E compact and Jordan measurable in R3.

[F7]

A bounded set in Rm is Jordan measurable iff its boundary is null, equivalently of content zero: A metric-bounded set ERm is Jordan measurable if and only if its boundary E is null, equivalently has content zero.

Proof

Given: The objects and hypotheses in the statement above.

1.1

Direct contraction gives ιFμ=FxdydzFydxdz+Fzdxdy. Differentiating gives (xFx+yFy+zFz)μ, so the volume-form divergence is the usual Euclidean divergence by the divergence-form identity, which has no choice hypothesis.

F5algebra
1.2

Evaluation of the contraction on (ru,rv) is det(F(r),ru,rv)=F(r)(ru×rv). This is precisely the published flux integrand. For an outward-oriented regular parametrization its cross product is outward.

F4algebra
1.3

The elementary-solid data make E a compact Jordan set, so E has content zero. As a compact manifold with boundary, E has finitely many connected components E1,,Em: connected relative coordinate balls and half-balls show that components are open, and compactness makes their open cover finite. Their interiors Uj=intR3Ej are connected and dense in Ej. Indeed, every point has a relative ball or half-ball whose interior part is connected and dense; closures of distinct interior components therefore cannot meet, and each such closure is relatively open, so connectedness of Ej permits only one. Each Uj is bounded and open, Uj=Ej, and UjE, so Uj is a Jordan domain.

F6F7given
2.1

Use in F2 the finite family of identity inclusions qj:Uj=EjE. Their restrictions are orientation-preserving diffeomorphisms onto the disjoint open subsets Uj of E, and their image closures cover E. Their target-coordinate representatives extend smoothly across parameter boundary points: boundary coordinates of a smooth full-dimensional embedded region are restrictions of local smooth ambient coordinates. Thus F2 applies to (divμF)μ. By step 1.1 its pullbacks have the usual scalar divergence as coefficient. Summing over Uj gives exactly the scalar integral over E: the omitted set is E of content zero, and finite additivity of the scalar Riemann integral applies to these disjoint pieces. Hence the two volume integrals coincide.

F2F6F7step 1.1step 1.3
3.1

Apply F1 on the compact smooth region E; FE has compact support and μ is positive for its specified orientation. It identifies the intrinsic boundary integral with this volume integral. Independently, F3 applies to the supplied elementary-solid data and the smooth field on O, identifying the classical presentation flux with the same scalar volume integral. Therefore the intrinsic boundary integral equals that presentation flux, and the two divergence theorems agree. Step 1.2 also identifies each patch's pointwise flux expression. The zero field gives zero throughout; if an empty region is allowed separately, both integrals are zero by the empty-sum convention.

F1F3step 1.2step 2.1

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