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Young's inequality at p=q=2 and at p=3, q=3/2

Example

(i) At the conjugate pair p=q=2, Young's inequality for products (rational conjugate exponents) reads ab≤a22+b22 for all a,b≥0, with equality exactly when a=b; the instance a:=4, b:=9 gives 36≤97/2.

(ii) At p:=3 and q:=3/2, conjugate since 13+23=1, it reads ab≤a33+23 b3/2; the instance a:=2, b:=4 gives 8 on both sides.

Facts & Assumptions

Given: Reals a,b≥0 for the general statements, the instance a=4, b=9 for (i), and the instance a=2, b=4 for (ii).

[L1]

Young's inequality (Young's inequality for products (rational conjugate exponents)): for conjugate rationals p,q>1, that is 1p+1q=1, and all reals a,b≥0, ab≤app+bqq, with the rational powers of Rational powers ar of a positive base and its supplementary clause 0p=0 for p>0.

[L2]

AM-GM (The arithmetic mean, geometric mean inequality): for n=2 and nonnegative entries u,v, uv≤(u+v)/2, equivalently uv≤((u+v)/2)2, with equality exactly when u=v. On positive entries, Weighted AM-GM inequality with rational weights with weights 1/2,1/2 gives the same inequality; its statement does not include an equality clause or zero bases.

[L3]

Roots and powers (Existence and uniqueness of n-th roots: a unique a1/n≥0 with (a1/n)n=a, Rational powers ar of a positive base, Laws of rational exponents): for c≥0, c1/2 is the unique nonnegative s with s2=c; u2v2=(uv)2 by the product law; and (41/2)3=43/2=8 since 41/2=2 and 23=8.

[L4]

Monotonicity of squaring (Squaring is monotone on the nonnegatives): for u,v≥0, u≤v holds exactly when u2≤v2; in particular a2=b2 with a,b≥0 gives a=b.

[L5]

Integer powers (Laws of integer exponents): a3=a2a and 23=8, 92=81, 42=16 by evaluation.

Verification

technique · direct
1.1L1algebra

Part (i), the inequality: p=q=2 are conjugate since 12+12=1, so [L1] gives ab≤a22+b22 for all a,b≥0.

1.2L2L3L4

Part (i), the equality clause, by AM-GM: for a,b≥0 the entries a2,b2 are nonnegative, their geometric mean is (a2b2)1/2=ab, because ab≥0 and (ab)2=a2b2 by [L3] make ab the unique nonnegative square root of a2b2, and their arithmetic mean is (a2+b2)/2; [L2] gives (a2+b2)/2≥ab with equality exactly when a2=b2, which for a,b≥0 holds exactly when a=b by [L4]; so equality in (i) is exactly a=b.

1.3L1L3L5algebra

Part (ii), the inequality and its instance: 13+23=1 by rational arithmetic, so [L1] applies at p=3, q=3/2; at a=2, b=4 the first term is a3/3=8/3 and the second is (2/3)b3/2=(2/3)(41/2)3=(2/3)⋅8=16/3 by [L3] and [L5], and the right-hand sum is 8/3+16/3=8=ab, so both sides are equal at this instance.

2.1step 1.2L5algebra

Part (i), the instance: a=4, b=9 give left-hand side 4⋅9=36 and right-hand side (16+81)/2=97/2, with 36=72/2≤97/2, and 4≠9 so the inequality is strict, consistent with the equality clause of step 1.2.

3.1step 1.1step 1.2step 2.1step 1.3L1L2∎

Summary: (i) holds with equality exactly at a=b (steps 1.1, 1.2) and the instance 4,9 is strict (step 2.1); (ii) holds at the conjugate pair 3,3/2 and its instance 2,4 has equality on both sides (step 1.3); the equality clause proved in (i) is a property of that instance of [L1] via AM-GM, not a claim about the general Young inequality.

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