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False statementConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
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FALSE: every functor preserves the ends that exist in its domain

Statement

False claim: if T:Cop×CD has an end and G:DE is any functor, then G carries that end to an end of GT (The end and the coend of a functor Cop×CD, Preservation, reflection, and creation of limits and colimits; continuous and cocontinuous functors).

Facts & Assumptions

Given: Two witnesses built from finite posets, regarded as categories, with monotone maps as functors.

[F5]

A preorder is a reflexive transitive relation, a map between preorders is monotone when it respects the order, and every partial order is a preorder (Preorder and monotone map).

[L2]

A preorder determines a category with at most one morphism between any two objects, and functors between such categories are exactly monotone maps (A preorder is a category with at most one morphism between any two objects, and its functors are exactly monotone maps).

[F2]

A product of (Ai)iI is an object P with projections pi such that every family fi:XAi has a unique pairing fiiI:XP,pifi=fi(iI) (Products and coproducts as limits and colimits of discrete diagrams, including their existence-and-uniqueness equations).

[F6]

A limit of a diagram is a terminal cone: explicitly, for every cone (X,ξ) there exists a unique morphism u:XL such that λju=ξj for every j; a product is the limit of a family on a discrete index category (Limits and colimits as terminal cones and initial cocones, with existence and uniqueness in their universal properties).

[F3]

A subcategory is full when A(A,B)=C(A,B) for every pair of its objects, so a full subcategory is determined entirely by its objects (Subcategory and full subcategory).

[F4]

G preserves J-limits if the image under G of every limiting cone over D:JC is limiting over GD (Preservation, reflection, and creation of limits and colimits; continuous and cocontinuous functors).

[F1]

An end of T is a terminal object of the category of wedges over T and a coend an initial object of the category of cowedges under T; in short, an end is a terminal wedge and a coend an initial cowedge (The end and the coend of a functor Cop×CD).

[L1]

For F:CD and F(c1,c2):=F(c2), the end of a functor made mute in its contravariant variable is the ordinary limit of that functor: cF(c,c)=limF (The end of a functor made mute in its contravariant variable is the ordinary limit of that functor).

[L3]

If G preserves Tw(C)-limits and T has an end, then G of that end is an end of GT, so a functor preserving twisted-arrow limits preserves ends (A functor preserving twisted-arrow limits preserves ends, and dually for coends).

Refutation

technique · direct
1.1

Regard a poset as a category by [L2] and [F5], so that a morphism ab exists exactly when ab and monotone maps are exactly the functors. Let C be the discrete category on two objects and let F:CP pick out two elements x and y of a poset P. By [F2] and [F6] a product of x and y in P is an element below both through which every element below both factors, that is a greatest lower bound; and by [L1] that product is the end of the mute functor F on Cop×C, since F has the same limit.

F1F2F5F6L1L2construct
2.1

First witness. Let P be the four-element poset {,x,y,} with <x<, <y< and x,y incomparable, and let Q be the two-element chain {0<1}. The map ϕ with ϕ()=0 and ϕ(x)=ϕ(y)=ϕ()=1 is monotone, hence a functor by [L2]. The greatest lower bound of x and y in P is , so by step 1.1 the end exists and is ; but the greatest lower bound of ϕ(x)=1 and ϕ(y)=1 in Q is 1, while ϕ()=0. So ϕ carries the end to an element that is not the end of the composite, and by [F4] it does not preserve it.

F4L2step 1.1
2.2

Second witness, with a full and faithful functor. Let P be the four-element poset {,m,x,y} with <m, m<x, m<y and x,y incomparable, so that the greatest lower bound of x and y in P is m. Let Q be the full subposet on {,x,y}, which by [F3] is a full subcategory, and in which the greatest lower bound of x and y is . The inclusion QP is monotone, hence a functor, and it carries the end computed in Q to , which is not the end m computed in P.

F3F4L2step 1.1
3.1

Each witness refutes the displayed claim, and neither uses anything infinite: both posets have four elements and every check is a comparison of two named elements. What is true is [L3]: a functor that preserves Tw(C)-limits preserves the ends indexed by C, and a right adjoint has that property for every C. Neither witness is a right adjoint.

F1L3step 2.1step 2.2

Remarks

The two witnesses fail in opposite directions and that is deliberate. In the first the image of the end is strictly below the end of the image; in the second it is strictly below as well, but the functor is a full and faithful inclusion, so fullness and faithfulness are not what is missing. What is missing in both cases is a hypothesis about limits, and only that.

A poset is the cheapest place to see the failure because a limit there is an order-theoretic infimum and a functor is a monotone map, so the whole question becomes whether a monotone map carries greatest lower bounds to greatest lower bounds. It plainly need not.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources