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False statementConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-08-26
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FALSE: every functor preserves the ends that exist in its domain

Statement

False claim: if T:Cop×C→D has an end and G:D→E is any functor, then G carries that end to an end of GT (The end and the coend of a functor Cop×C→D, Preservation, reflection, and creation of limits and colimits; continuous and cocontinuous functors).

Facts & Assumptions

Given: Two witnesses built from finite posets, regarded as categories, with monotone maps as functors.

[F5]

A preorder is a reflexive transitive relation, a map between preorders is monotone when it respects the order, and every partial order is a preorder (Preorder and monotone map).

[L2]

A preorder determines a category with at most one morphism between any two objects, and functors between such categories are exactly monotone maps (A preorder is a category with at most one morphism between any two objects, and its functors are exactly monotone maps).

[F2]

A product of (Ai)i∈I is an object P with projections pi such that every family fi:X→Ai has a unique pairing ⟨fi⟩i∈I:X→P,pi⟨fi⟩=fi(i∈I) (Products and coproducts as limits and colimits of discrete diagrams, including their existence-and-uniqueness equations).

[F6]

A limit of a diagram is a terminal cone: explicitly, for every cone (X,ξ) there exists a unique morphism u:X→L such that λju=ξj for every j; a product is the limit of a family on a discrete index category (Limits and colimits as terminal cones and initial cocones, with existence and uniqueness in their universal properties).

[F3]

A subcategory is full when A(A,B)=C(A,B) for every pair of its objects, so a full subcategory is determined entirely by its objects (Subcategory and full subcategory).

[F4]

G preserves J-limits if the image under G of every limiting cone over D:J→C is limiting over GD (Preservation, reflection, and creation of limits and colimits; continuous and cocontinuous functors).

[F1]

An end of T is a terminal object of the category of wedges over T and a coend an initial object of the category of cowedges under T; in short, an end is a terminal wedge and a coend an initial cowedge (The end and the coend of a functor Cop×C→D).

[L1]

For F:C→D and F′(c1,c2):=F(c2), the end of a functor made mute in its contravariant variable is the ordinary limit of that functor: ∫cF′(c,c)=lim⁡F (The end of a functor made mute in its contravariant variable is the ordinary limit of that functor).

[L3]

If G preserves Tw⁡(C)-limits and T has an end, then G of that end is an end of GT, so a functor preserving twisted-arrow limits preserves ends (A functor preserving twisted-arrow limits preserves ends, and dually for coends).

Refutation

technique · direct
1.1F1F2F5F6L1L2construct

Regard a poset as a category by [L2] and [F5], so that a morphism a→b exists exactly when a≤b and monotone maps are exactly the functors. Let C be the discrete category on two objects and let F:C→P pick out two elements x and y of a poset P. By [F2] and [F6] a product of x and y in P is an element below both through which every element below both factors, that is a greatest lower bound; and by [L1] that product is the end of the mute functor F′ on Cop×C, since F′ has the same limit.

2.1F4L2step 1.1

First witness. Let P be the four-element poset {⊥,x,y,⊤} with ⊥<x<⊤, ⊥<y<⊤ and x,y incomparable, and let Q be the two-element chain {0<1}. The map ϕ with ϕ(⊥)=0 and ϕ(x)=ϕ(y)=ϕ(⊤)=1 is monotone, hence a functor by [L2]. The greatest lower bound of x and y in P is ⊥, so by step 1.1 the end exists and is ⊥; but the greatest lower bound of ϕ(x)=1 and ϕ(y)=1 in Q is 1, while ϕ(⊥)=0. So ϕ carries the end to an element that is not the end of the composite, and by [F4] it does not preserve it.

2.2F3F4L2step 1.1

Second witness, with a full and faithful functor. Let P′ be the four-element poset {⊥,m,x,y} with ⊥<m, m<x, m<y and x,y incomparable, so that the greatest lower bound of x and y in P′ is m. Let Q′ be the full subposet on {⊥,x,y}, which by [F3] is a full subcategory, and in which the greatest lower bound of x and y is ⊥. The inclusion Q′→P′ is monotone, hence a functor, and it carries the end ⊥ computed in Q′ to ⊥, which is not the end m computed in P′.

3.1F1L3step 2.1step 2.2∎

Each witness refutes the displayed claim, and neither uses anything infinite: both posets have four elements and every check is a comparison of two named elements. What is true is [L3]: a functor that preserves Tw⁡(C)-limits preserves the ends indexed by C, and a right adjoint has that property for every C. Neither witness is a right adjoint.

Remarks

The two witnesses fail in opposite directions and that is deliberate. In the first the image of the end is strictly below the end of the image; in the second it is strictly below as well, but the functor is a full and faithful inclusion, so fullness and faithfulness are not what is missing. What is missing in both cases is a hypothesis about limits, and only that.

A poset is the cheapest place to see the failure because a limit there is an order-theoretic infimum and a functor is a monotone map, so the whole question becomes whether a monotone map carries greatest lower bounds to greatest lower bounds. It plainly need not.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources