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Verma modules need not be finite-dimensional
Statement
Assume the Axiom of Choice. Every Verma module for a complex semisimple Lie algebra is finite-dimensional.
Facts & Assumptions
Given: The Axiom of Choice, with basis and bracket , , (The special linear Lie algebra sl_2, The root sl_2 triple), the Borel subalgebra (Positive and negative nilpotent subalgebras and the Borel), and the functional on with . In this item the Verma module attached to is the induced module ; for and we realise it concretely as , where is the left ideal generated by and , with (Universal enveloping algebra, Highest-weight vectors and modules).
The Axiom of Choice is assumed; it enters through the root-space and highest-weight theory used below (The Axiom of Choice).
The set is an ordered basis of , so by PBW the monomials form a basis of , and the monomials with form a basis of , the enveloping algebra of the span of (Poincaré–Birkhoff–Witt theorem).
In the quotient one has and , because ; and is the class of . [definition of ]
Refutation
The classes of the monomials , , are linearly independent in : let be the linear map sending a PBW monomial to when and and to otherwise, so that for ; then vanishes on , because every element of has zero component along in the ordered PBW basis of [L1], and for with , , the component of along equals the augmentation ; hence forces and all .
Therefore the vectors , , form an infinite linearly independent family in ; in particular is infinite-dimensional.
Since is a Verma module (it is the induced module in the realisation above) and its dimension is infinite, the universal statement of the Statement section is false.
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
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Sources
- Anthony W. Knapp, Lie Groups Beyond an Introduction, 2nd ed. (standard reference, not scraped)
- Alexander Kirillov Jr., An Introduction to Lie Groups and Lie Algebras (standard reference, not scraped)