Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedaudited 2026-09-22
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Verma modules need not be finite-dimensional

Statement

Assume the Axiom of Choice. Every Verma module for a complex semisimple Lie algebra is finite-dimensional.

Facts & Assumptions

Given: The Axiom of Choice, sl2(C) with basis e,f,h and bracket [e,f]=h, [h,e]=2e, [h,f]=2f (The special linear Lie algebra sl_2, The root sl_2 triple), the Borel subalgebra b=ChCe (Positive and negative nilpotent subalgebras and the Borel), and the functional λ=0 on b with λ(b)=0. In this item the Verma module attached to λ is the induced module M(λ)=U(sl2)U(b)Cλ; for sl2 and λ=0 we realise it concretely as M=U(sl2)/J, where J is the left ideal generated by e and h, with v=1+J (Universal enveloping algebra, Highest-weight vectors and modules).

[A1]

The Axiom of Choice is assumed; it enters through the root-space and highest-weight theory used below (The Axiom of Choice).

[L1]

The set {f,h,e} is an ordered basis of sl2, so by PBW the monomials fahbec form a basis of U(sl2), and the monomials fk with k0 form a basis of U(Cf), the enveloping algebra of the span of f (Poincaré–Birkhoff–Witt theorem).

[L2]

In the quotient M=U(sl2)/J one has ev=0 and hv=0, because e,hJ; and fkv is the class of fk. [definition of M]

Refutation

technique · direct
1.1

The classes of the monomials fk, k0, are linearly independent in M: let π:U(sl2)U(Cf) be the linear map sending a PBW monomial fahbec to fa when b=0 and c=0 and to 0 otherwise, so that π(u)=u for uU(Cf); then π vanishes on J=U(sl2)e+U(sl2)h, because every element of U(sl2)e has zero component along fa in the ordered PBW basis of [L1], and for uh with u=AfAuA, uAU(hCe), the component of fAuAh along fA equals the augmentation ε(uAh)=ε(uA)ε(h)=0; hence kckfkJ forces kckfk=π(kckfk)=0 and all ck=0.

L1L2A1
2.1

Therefore the vectors fkv, k0, form an infinite linearly independent family in M; in particular M is infinite-dimensional.

L2step 1.1
3.1

Since M is a Verma module (it is the induced module U(sl2)U(b)C0 in the realisation above) and its dimension is infinite, the universal statement of the Statement section is false.

step 2.1

Depends on

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